How many number of possible binary search trees are obtained if the number of keys?

How many number of possible binary search trees are obtained if the number of keys?

Total number of possible Binary Search Trees and Binary Trees with n keys. Total number of possible Binary Search Trees with n different keys (countBST(n)) = Catalan number Cn = (2n)! / ((n + 1)!

What is the time complexity of find algorithm is a binary search tree with N nodes and height h?

The binary search tree is a balanced binary search tree. Height of the binary search tree becomes log(n). So, Time complexity of BST Operations = O(logn).

Where is the maximum number in a binary search tree?

In Binary Search Tree, we can find maximum by traversing right pointers until we reach the rightmost node. But in Binary Tree, we must visit every node to figure out maximum. So the idea is to traverse the given tree and for every node return maximum of 3 values.

How many levels are there in binary tree?

For complete or full binary trees, the number of levels is always 1 + floor(log_2(n)) , because the shape of the tree depends only on n . If you label the nodes with an index in breadth-first order, you can compute the level without any traversal in O(1) time.

How many trees are possible with N nodes?

In general: If there are n nodes, there exist 2^n-n different trees.

How many binary trees are possible with N nodes?

In general, if there are n nodes, there exist (2n)!/(n+1)! different trees.

What is the complexity of searching for a key in a binary search tree?

O
In any binary search tree the time complexity taken is O(h), where h is the height of the tree.. Since it is given that tree is balanced binary search tree so searching for an element in worst case is O(logn).

Why is the second tree not a binary search tree?

Also, the values of all the nodes of the right subtree of any node are greater than the value of the node. In the above picture, the second tree is not a binary search tree because all the values of all the nodes of the left subtree are not smaller than all the nodes of the right subtree.

What is the best way to count numbers in binary search tree?

A Better Solution is to augment every tree node to store count together with regular fields like key, left and right pointers. Insertion of keys 12, 10, 20, 9, 11, 10, 12, 12 in an empty Binary Search Tree would create following. This approach has following advantages over above simple approach.

What is the Order of insertion in a binary search tree?

The numbers 1, 2, …, n are inserted in a binary search tree in some order. In the resulting tree, the right subtree of the root contains p nodes. The first number to be inserted in the tree must be- Let n = 4 and p = 3.

What is the first number to be inserted in the tree?

The first number to be inserted in the tree must be- Let n = 4 and p = 3. Clearly, first inserted number = 1. Thus, Option (C) is correct. We are given a set of n distinct elements and an unlabeled binary tree with n nodes.