What is the coefficient of x in the expansion of x 2?

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What is the coefficient of x in the expansion of x 2?

The coefficient of x² is -6. Therefore, the coefficient of x² is -6.

What is the coefficient of X in X square x 1?

so, the coefficient of x is -1.

What is the coefficient of X 9 in the expansion?

Find the coefficient of x9 in the expansion of (1+x)(1+x2)(1+x3).. (1+x100). The official answer is 8.

What is coefficient of X in?

For example, in the expression 3x, 3 is the coefficient but in the expression x2 + 3, 1 is the coefficient of x2. In other words, a coefficient is a multiplicative factor in the terms of a polynomial, a series, or any expression. It is generally a number.

How do you find the coefficient of x 2?

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It is usually an integer that is multiplied by the variable next to it. Coefficient of x² is 1. Coefficient of x² is -1. Coefficient of x² is π/2.

What is the coefficient from X Square 1?

A coefficient refers to a number or quantity placed with a variable. It is usually an integer that is multiplied by the variable next to it. Coefficient of x² is 1. Coefficient of x² is -1.

What is the coefficient of X in the product x 1 )( 1 2x?

Hence, the coefficient of x is 3.

What is the coefficient of x8y9?

What is the coefficient of x8y9? )35(−2)13 = −17055940608 Meanwhile, 8 + 9 = 18, so no terms of the form cx8y9 arise in the binomial expansion, so in other words the coefficient of x8y9 is 0. ). Let S be a set of size n.

What is the coefficient of x^99?

In the polynomial expression (x-1). (x-2). (x-3)….. (x-100) the first term (coefficient of x^100 ) is 1 , the second term (coefficient of x^99 is the sum of the roots i.e., 1+2+3+4+…..+99+100 = 5050 . Thus , the coefficient of x^99 is -5050.

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When constant term will be taken from (x+3) COFF of X99?

So, when constant will be taken from (x+1) coff. of $$x^{99} will be 1 when constant term will be taken from (x+3) coff. of x99will be 3 Similarly, When constant term will be taken from (x+199) coff. of x99will be 199.

What is the sum of all cases of X in X^99?

For x^99, the term is got by choosing the constant in one of the 100 factors, and the rest x. Hence similarly you have 100 cases. Hence sum of all will be -x (1+2+3+ …… +100) which is -5050x Each x has to be multiplied with 98 other x’s and one constant.

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