What are the mole fractions of NaCl and water?

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What are the mole fractions of NaCl and water?

Mole Fraction in Solutions Mole fraction can also be applied in the case of solutions. For example, 0.100 moles of NaCl are dissolved in 100.0 mL of water. What is the mole fraction of NaCl? We find that the mole fraction of NaCl is 0.0176.

How do you find the mole fraction of NaCl solution?

A mole fraction, as the name implies, is a comparison of the number of moles in solution. It is found by taking the number of moles of solutes (or solvent) divided by the total number of moles (solutes + solvent). Since this is a fraction, there are no units.

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What is the mole fraction of NaCl in a mixture?

0.361
The mole fraction of NaCl in the mixture is 0.361 .

What is the mole fraction of pure water?

Ans: Mole fraction of water is 0.71 and the mole fraction of ethanol is 0.29.

What is mole fraction class 12?

Class 12 Chemistry Solutions. Mole fraction. Mole fraction. Mole fraction can be defined as the ratio of number of moles of the component in the solution to the total number of moles of all components in the solution.

How do you calculate mole fraction?

Mole fraction (Xsolute) = moles of solute / (moles of solute + moles of solvent) .

How do you find the mole fraction in chemistry?

How do you find the mole fraction of NaCl in water?

Solved examples. 1. Calculate the mole fraction of NaCl and H 2 O, if 0.010 moles of NaCl is dissolved in 100 grams of pure water. Answer: Mole fraction of NaCl is 0.018 and the mole fraction of water is 0.982. Solution: The molecular weight of water = 18.0153 grams per mole.

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How do you calculate the mole fraction of sugar and water?

Calculate the mole fractions of sugar and water. Solution: 1) Molality is moles solute / kg of solvent. Therefore we know our solution is: 1.62 mol C12H22O11 1.00 kg = 1000 g of water 2) Calculate the moles of water present: 1000 g / 18.0152 g/mol = 55.50868 mol 3) Determine the mole fraction of the sugar:

How many G of sodium chloride is dissolved in 1000g of water?

5 gms of sodium chloride was dissolved in 1000 gms of water. If the density of resulting solution is 0.997, calculate (a) Molarity (b) Molality (c) Mole fraction of the solute (At wt of N a = 23,C L = 35.5,H = 1,D = 16) Was this answer helpful?

How to calculate the molality of the solution?

Solution: 1) Molality is moles solute / kg of solvent. Therefore we know our solution is: 1.62 mol C12H22O11 1.00 kg = 1000 g of water 2) Calculate the moles of water present: 1000 g / 18.0152 g/mol = 55.50868 mol 3) Determine the mole fraction of the sugar: 1.62 mol / (1.62 mol + 55.50868 mol) = 0.028357 = 0.0284 (to three SF)

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