Table of Contents
How do you find the area of an isosceles triangle?
The area of an isosceles triangle can be calculated in many ways based on the known elements of the isosceles triangle.
- Using base and Height: Area = ½ × b × h.
- Using all three sides: Area = ½[√(a2 − b2 ⁄4) × b]
- Using the length of 2 sides and an angle between them: Area = ½ × b × a × sin(α)
How do you find the perimeter of an isosceles triangle?
Since an isosceles triangle has two equal sides, its perimeter can be calculated if the base and the equal sides are known. The formula to calculate the perimeter of an isosceles triangle is P = 2a + b where ‘a’ is the length of the two equal sides and ‘b’ is the base of the triangle.
What is the formula of isosceles?
List of Formulas to Find Isosceles Triangle Area
Formulas to Find Area of Isosceles Triangle | |
---|---|
Using base and Height | A = ½ × b × h |
Using all three sides | A = ½[√(a2 − b2 ⁄4) × b] |
Using the length of 2 sides and an angle between them | A = ½ × b × c × sin(α) |
How do you find the angles of an isosceles triangle with 3 sides?
To solve an SSS triangle:
- use The Law of Cosines first to calculate one of the angles.
- then use The Law of Cosines again to find another angle.
- and finally use angles of a triangle add to 180° to find the last angle.
What is the rule for an isosceles triangle?
The rule for an isosceles triangle is that the triangle must have two sides of equal length. These two sides are called the legs of the triangle and the unequal side is called the base. The isosceles triangle theorem further states that the angles opposite to each of the equal sides must also be equal.
How to prove that a triangle is an isosceles triangle?
Theorem 2: Sides opposite to the equal angles of a triangle are equal. Proof: In a triangle ABC, base angles are equal and we need to prove that AC = BC or ∆ABC is an isosceles triangle. Construct a bisector CD which meets the side AB at right angles. Or ∆ABC is isosceles.
What are the angles opposite to the equal sides of isosceles?
Theorem 1: Angles opposite to the equal sides of an isosceles triangle are also equal. Proof: Consider an isosceles triangle ABC where AC = BC. We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA. We first draw a bisector of ∠ACB and name it as CD.
Is triangle BCD is an isosceles triangle?
Using coordinate geometry, prove that triangle BCD is an isosceles triangle . Triangle ABC has coordinate A (-2,3) , B (-5,-4) and C (2,-1). Using coordinate geometry , prove that triangle BCD is an isosceles triangle.