How many 3 letter code words are possible using the first 8 letters of the alphabet if a no letter can be repeated b letters can be repeated C adjacent letters Cannot be alike?

How many 3 letter code words are possible using the first 8 letters of the alphabet if a no letter can be repeated b letters can be repeated C adjacent letters Cannot be alike?

Assuming you can use letters as many times as you want (ex. AAA is allowed), AND different combinations of letters are the different (i.e. AAB ≠ ABA), the answer will be , or 512.

How many 3 letter code words can be made from the letters B C D E and F if repetition of a letter is allowed?

If letters can be repeated as many times as you want, there are 6 options (A, B, C, D, E, or F) for the first letter, second letter, and third letter. Then 63=216 are the number of options for all three-letter-words.

How many 3 letter code can be formed using the first 10 letters of the English alphabet if no letter can be repeated?

5040 four lettered codes
The third place can be filled with any of the remaining 8 letters in 8 different ways and the fourth place can be filled by any of the remaining 7 letters in 7 different ways. Hence, 5040 four lettered codes can be formed using the first 10 letters of the English alphabet, if no letter is repeated. ways.

How many 3 letter code words are possible using the first 10 letters of English alphabets if I no letter can be repeated II letters are repeated?

Therefore a total of 720 ways is possible. Note: We can also find these type of question by directly using the permutation formula i.e., nPr=n!

How many 3 letter words can be created if repetitions are allowed?

So, the required number of 3-letter words =(5×4×3)=60. (ii) When repetition of letters is allowed, each place can be filled by any of the 5 letters in 5 ways. ∴ the required number of ways =(5×5×5)=125.

How many different word of three letter can be formed using the letter of the word English without repetition?

=720. Hence, the no. of 3 letter words formed from the word LOGARITHMS without repetition is 720. Hence the correct option of this question is option (a).

How many combinations of letters are there in the alphabet?

For each choice you have 26 options (the letters in the alphabet). So the total number of combinations is 26 ⋅ 26 ⋅ 26 = 26 3 = 17576. If you want the letters to be unique, the calculation changes slightly.

How many combinations can you make with 3 letters in Excel?

You can make three independent choices, one for each of the three letters. For each choice you have 26 options (the letters in the alphabet). So the total number of combinations is 26 ⋅ 26 ⋅ 26 = 26 3 = 17576. If you want the letters to be unique, the calculation changes slightly.

How many possible combinations can you make with a string?

Note that string doesn’t have to be unique, it can be eg. RPP or AZZ sol: You can make three independent choices, one for each of the three letters. For each choice, you have 26 options (the letters in the alphabet). So the total number of combinations is

How many ways can you choose a 3 letter combo?

First letter of he 3 letter combo can be chosen in 8 ways. Third letter can be chosen in 6 ways.