Table of Contents
How many states are required to construct DFA which accepts all the strings containing Substrings ABA?
All strings starting with ‘n’ length substring will always require minimum (n+2) states in the DFA.
How can make DFA in regex?
This method is given below: Step 1: Design a transition diagram for given regular expression, using NFA with ε moves. Step 2: Convert this NFA with ε to NFA without ε. Step 3: Convert the obtained NFA to equivalent DFA.
How many number of states are there in a minimal DFA that accepts the strings that end with AB?
The answer given is 8.
How do I draw a DFA containing 101 as substring?
- Basically we need to design an automata that accepts language containing strings which have ‘101’ as substring.
- The final solution is as shown below-
- Where, q0 = Initial State.
- Q = Set of all states {q0, q1, q2, q3}
- q3 = Final State.
- 0,1 are input alphabets.
- Let us understand the above solution step by step –
What is the minimum number of states for a DFA that generates all the strings of an alphabet?
Ques-3: What is the minimum number of states in deterministic finite automata (DFA) for string starting with ba2 and ending with ‘a’ over alphabet {a, b}? Explanation: In the above DFA, minimum number of states required is six. Option (D) is correct.
How do you convert NFA to NFA?
To remove the epsilon move/Null move from epsilon-NFA and to convert it into NFA, we follow the steps mentioned below.
- Figure – Vertex v1 and Vertex v2 having an epsilon move.
- Figure – State q0 as vertex v1 and state q2 as vertex v2.
- Figure – NFA on duplicating moves.
- Figure – NFA after making state q2 as a start state.
Can we convert DFA to NFA?
Yes, every DFA can be converted (and actually trivially is) an NFA.
How do you create an NFA in automata?
It is easy to construct an NFA than DFA for a given regular language. The finite automata are called NFA when there exist many paths for specific input from the current state to the next state. Every NFA is not DFA, but each NFA can be translated into DFA….Example 1:
- Q = {q0, q1, q2}
- ∑ = {0, 1}
- q0 = {q0}
- F = {q2}