How many three digit integers are there in which the first digit from left is greater than the second digit and the second digit is greater than the third digit?

How many three digit integers are there in which the first digit from left is greater than the second digit and the second digit is greater than the third digit?

The answer is 285. List all the three-digit integers in r where the first digit is greater than the second or third digit.

How many 3-digit numbers are there such that exactly two of the digits are equal to each other?

Third digit can be filled with remaining 8 digits. Hence the number of three digit numbers formed such that at least 2 of its digits are same are 252.

How many positive integers of at most 3 digits are there such that the product of their digits is 30?

given abc=252. the possible options are (4,7,9)(4,9,7)(7,9,4)(7,4,9)(9,7,4)(9,4,7)(6,7,6) (6,6,7)(7,6,6) hence there are 9 possibilities.

How many 3 digit integers are there?

Therefore there are 900 three-digit numbers in all.

How many positive integers are there between 106 and 107?

How many different positive integers exist between 10^6 : Problem Solving (PS)

How many three digit numbers ABC are formed where two of the three digits are same?

Which is the largest 3 digit number?

999
Therefore the largest three digit number is 999.

What is the greatest 3 digit number?

The greatest three-digit number is 999 but what do we have to find?

How many 3-digit integers are greater than 700?

Also, there are 299 3-digit integers greater than 700. How many of these do not have exactly two digits equal to each other? There are 3 such integers that have three digits equal to each other (777,888,999) and 3 x 9 x 8 =216 that feature three distinct digits.

How many values can a three-digit integer take?

Since given three-digit integers must be greater than 700, then the first digit can take three values: 7, 8, or 9. The second digit can take 9 values: 10 digits minus one digit we’ve already used for the first digit. Similarly, the third digit can take 8 values: 10 digits minus two digits we’ve already used for the first and second digits.

How do you find the number of integers with the same numbers?

Integers with exactly 2 digits the same = Total integers – Integers with all 3 digits the same – Integers with all 3 digits different. Number of integers = biggest – smallest + 1. Total = 999 – 701 + 1 = 299.

How many possible first and second and third digits are there?

There are 9 possible first digits (I’m not counting 012 as a three digit number). There are 10 possible second digits. There are 10 possible third digits. Either the first and second (90), first and third (90), or second and third (90) must match.