Table of Contents
- 1 What is the minimum and maximum number of nodes in an AVL tree of height 6?
- 2 What are the minimum number of nodes allowed in an AVL tree of height 4?
- 3 What is the maximum number of nodes in AVL tree of height 5?
- 4 What is the maximum number of nodes in a B tree of order m and height h?
- 5 What is the minimum and maximum height of a binary tree with seven nodes?
- 6 What is the minimum number of nodes in a complete binary tree with height 3?
- 7 What is the maximum number of nodes in an AVL tree?
- 8 What are the different types of questions based on AVL trees?
What is the minimum and maximum number of nodes in an AVL tree of height 6?
the minimum number of nodes in an AVL tree for a tree with a height of 6 is not 20, it should be 33. The following equation should demonstrate the recursive call of the N(h) function.
What are the minimum number of nodes allowed in an AVL tree of height 4?
12
The minimum number of nodes is 12. initially empty AVL tree has keys 1 through 7 inserted in order.
What is the maximum and minimum height of a tree with n nodes?
In a binary tree, a node can have maximum two children. If there are n nodes in binary tree, maximum height of the binary tree is n-1 and minimum height is floor(log2n).
What is the maximum height of an AVL tree with 10 nodes?
But given number of nodes = 10 which is less than 12. Thus, maximum height of AVL tree that can be obtained using 10 nodes = 3.
What is the maximum number of nodes in AVL tree of height 5?
If there are n nodes in AVL tree, maximum height can’t exceed 1.44*log2n. If height of AVL tree is h, maximum number of nodes can be 2h+1 – 1.
What is the maximum number of nodes in a B tree of order m and height h?
The maximum children a root node can have is m (order), so that’s 128. And each of those 128 children have 128 children, so that gives us a total of 1+128+16384=16512 total nodes. According to Wikipedia, a B-tree of n nodes can store n-1 keys, so that leaves us with a maximum of 16511 keys.
What is the minimum number of nodes in an AVL tree?
If height of AVL tree is h, maximum number of nodes can be 2h+1 – 1. Minimum number of nodes in a tree with height h can be represented as: N(h) = N(h-1) + N(h-2) + 1 for n>2 where N(0) = 1 and N(1) = 2.
What is the minimum number of nodes in a complete binary tree with depth 3?
7 nodes
Answer: A perfect binary tree of height 3 has 23+1 – 1 = 15 nodes. Therefore it requires 300 bytes to store the tree. If the tree is full of height 3 and minimum number of nodes, the tree will have 7 nodes.
What is the minimum and maximum height of a binary tree with seven nodes?
Detailed Solution If there are n nodes in binary tree, maximum height of the binary tree is n-1.
What is the minimum number of nodes in a complete binary tree with height 3?
What is the minimum number of nodes in AVL trees of height 5?
What is height of AVL tree?
The height of an AVL tree is bounded by roughly 1.44 * log2 N, while the height of a red-black tree may be up to 2 * log2 N.
What is the maximum number of nodes in an AVL tree?
If there are n nodes in AVL tree, maximum height can’t exceed 1.44*log 2n. If height of AVL tree is h, maximum number of nodes can be 2 h+1 – 1. Minimum number of nodes in a tree with height h can be represented as: N (h) = N (h-1) + N (h-2) + 1 for n>2 where N (0) = 1 and N (1) = 2.
What are the different types of questions based on AVL trees?
We have discussed types of questions based on AVL trees. Given number of nodes, the question can be asked to find minimum and maximum height of AVL tree. Also, given the height, maximum or minimum number of nodes can be asked. Que – 1. What is the maximum height of any AVL-tree with 7 nodes?
What is AVL tree in DBMS?
AVL tree is binary search tree with additional property that difference between height of left sub-tree and right sub-tree of any node can’t be more than 1. Here are some key points about AVL trees:
How to find the maximum height of a node in a tree?
That height is the minimum. To find the maximum, do the same as for the minimum, but then go back one step (remove the last placed node) and see if adding that node to the opposite sub-tree (from where it just was) violates the AVL tree property. If it does, your max height is just your min height.