Table of Contents
- 1 How many ways can 5 prizes be distributed to 8 students if each student can get any number of prizes?
- 2 How many ways can 5 prizes be distributed among four students when every student can take one or more prizes?
- 3 How many ways can 4 prizes be distributed among 3 students if each student can get all the 4 prizes?
- 4 How many ways can we select five door prizes from seven different ones and distribute them among five people?
- 5 How many ways three prizes out of 5 can be distributed among three brothers equally?
- 6 How many ways can 4 prizes be given away to 3 girls if each girl is eligible for all the prizes?
- 7 How many prizes can be distributed in (8/1)?
- 8 How many students are there in each prize?
How many ways can 5 prizes be distributed to 8 students if each student can get any number of prizes?
Same applies to the C prize case. Therefore, the answer would be 12 x 12 x 12 = 1728.
How many ways can 5 prizes be distributed among four students when every student can take one or more prizes?
The answer says 1024, which I guess is coming from 45. So its like “4 students fit into each prize” + repeats allowed + 5 prizes =45=1024.
How many ways can 8 prizes be given away 27 student if each student is eligible for all the prices?
So total ways would be 8! = 8*7*6*5*4*3*2*1 = 40320.
How many ways 8 students can be given 3 prizes such that no student receives more than 1 prize?
In how many ways 8 students can be given 3 prizes such that no student receives more than 1 prize? 348.
How many ways can 4 prizes be distributed among 3 students if each student can get all the 4 prizes?
Any one prize can be given to any one of the 3 boys and hence there are 3 ways of distributing each prize. Hence, the 4 prizes can be distributed in 34= 81 ways.
How many ways can we select five door prizes from seven different ones and distribute them among five people?
How many ways can five different door prizes be distributed among five people? There are 5 choices of prize for the first person, 4 choices for the second, and so on. The number of ways the prizes can be distributed will be 5! = 5 · 4 · 3 · 2 · 1 = 120 ways.
How many ways can you arrange 7 chocolate biscuits 12?
Discussion Forum
| Que. | How many ways are there to arrange 7 chocolate biscuits and 12 cheesecake biscuits into a row of 19 biscuits? |
|---|---|
| b. | 50388 |
| c. | 87658 |
| d. | 24976 |
| Answer:50388 |
How many ways can 10 boys be seated in a row having 28 seats such that no two friends occupy adjacent seats?
Discussion Forum
| Que. | In how many ways can 10 boys be seated in a row having 28 seats such that no two friends occupy adjacent seats? |
|---|---|
| b. | ⁹P₂₉ |
| c. | ¹⁹P₁₀ |
| d. | ¹⁵P₇ |
| Answer:¹⁹P₁₀ |
How many ways three prizes out of 5 can be distributed among three brothers equally?
= 6 ways. Thus, there are (10 * 6) = 60 possible ways for each arrangement of boys.
How many ways can 4 prizes be given away to 3 girls if each girl is eligible for all the prizes?
(i) The 1st prize can be given to anyone of the 4 girls in 4 ways. Similarly, the second prize can be given in 3 ways and the 3rd prize can be given in 2 ways. ∴ the required number of ways=(4×3×2)=24.
How many ways can 8 prizes be given away to 7 students if each student is eligible for all the prizes 1 point?
So total ways would be 8! = 8*7*6*5*4*3*2*1 = 40320. Hence, the 7 prizes can be distributed in 40320 ways.
How many ways can we select five door prizes from six different ones and distribute them among five people?
How many prizes can be distributed in (8/1)?
A prize can be given to any one of the 8 students in (8/1)=8 ways So, each prize can be distributed in (8/1)=8 ways 5 prizes can be distributed in (8/1)× (8/1)× (8/1)× (8/1)× (8/1) = 8 power 5
How many students are there in each prize?
Each prize comes with a list of four students. When the judge awards the first prize, she chooses one of the four to win the prize. When she awards the second prize, there are again four choices.
How many different medals can be awarded to the 8 runners?
Using the Basic Counting Rule, there are 8 choices for the gold medal winner, 7 remaining choices for the silver, and 6 for the bronze, so there are 8 · 7 · 6 = 336 ways the three medals can be awarded to the 8 runners.