At what angle will a projectile has its max height and range equal to each other?

At what angle will a projectile has its max height and range equal to each other?

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

What is the angle of projection for which the maximum height is equal to half of the horizontal range?

Answer: there is only and acceleration equal to ji getting vertically downwards on the object . the horizontal component of the velocity does not change .. if the angle of projection is 75. 96 degrees maximum height is equal to the horizontal range …….

For what angle of a projectile is its range equal to zero?

Range of projectile, R For projection above ground surface, the range of the angle of projection with respect to horizontal direction, θ, is 0° ≤ θ ≤ 90° and the corresponding range of 2θ is 0° ≤ 2θ ≤ 180°.

What is the relation between maximum height and maximum range?

The maximum height of a projectile is half of its range on the horizontal.

When a projectile reaches maximum height?

zero vertical
The maximum height of the projectile is when the projectile reaches zero vertical velocity. From this point the vertical component of the velocity vector will point downwards. The horizontal displacement of the projectile is called the range of the projectile and depends on the initial velocity of the object.

What is the formula of maximum height in projectile motion?

h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.

What is the angle of projection of projectile for maximum height?

As you can see from the figure, the larger the initial launch angle, the closer the object comes to maximum height and the longer the flight time. The largest range will be experienced at a launch angle up to 45 degrees.

What is the relationship between the range and the height of the projectile?

Increasing the launch height increases the downward distance, giving the horizontal component of the velocity greater time to act upon the projectile and hence increasing the range. “

What is the formula of maximum height of projectile?

h = v 0 y 2 2 g . h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.

What is the maximum range of a projectile with initial velocity?

2 θ 0 = 90 0 o r, θ 0 = 45 0 Thus the horizontal range of a projectile for a given initial velocity is maximum when it is projected at an angle of 45 0 with the horizontal. The maximum range of projectile formula To find the formula for a maximum range put θ 0 = 45 0 in equation (1).

Can a projectile of the same mass be launched at different angles?

A projectile of the same mass can be launched with the same initial velocity and different angles θ 0. Consider the figure given below where a projectile is launched with three different angles 45 0, 60 0, a n d 30 0. From the above figure, we can clearly see that for different angles of projection horizontal range of projectile is different.

Why is the range of a projectile symmetrical?

Since we are neglecting air resistance, the motion is symmetrical. The projectile hits the ground in TWICE the time it takes to get to its maximum height.) Range= (2 v0 2 /g)sin (θ)cos (θ).

How do you find the horizontal range of a projectile?

We know that the horizontal range of a projectile is the distance traveled by the projectile during its time of flight. This horizontal range is given by the relation Horizontal Range = Horizontal velocity × time of flight So, the formula for the horizontal range is R = v 0 2 sin