Table of Contents
What is the probability of a basketball player hitting a free throw?
Assume that fr Question 339175: A basketball player has a 70\% free throw shooting average, which can be interpreted to mean that the probability of his hitting any single free throw is 0.7 or 7/10. Assume that free throws are independent events, so that what happens on one free throw doesn’t affect the outcome of the next.
How many shots should a guard take in a basketball workout?
A great basketball workout for all guards. Make shots shooting from the following specific distances: • 10 shots from 3 feet. • 5 shots from 5 feet. • 5 shots from 7 feet. Using your complete free-throw routine, make 5 free-throws.
How many drills are in a basketball workout?
This workout consists of 10 drills that are to be completed consecutively to make up one circuit. It incorporates dribbling and footwork skills to go along with shooting and can be done as an individual with a designated passer or with another player.
How do you shoot a layup high in basketball?
Stand under the basket with your back towards the baseline. Begin by shooting a layup with your right hand and then catch the basketball high as soon as the shot falls through the net.
What is the expected percentage of foul shots a basketball player makes?
A basketball player has made 75\% of his foul shots during the season. Assuming the shots are independent, find the expected number of shots until he misses. 0.25
What is the probability of hitting the Bullʹs-eye on the 5th Arrow?
An archer is able to hit the bullʹs-eye 71\% of the time. If she shoots 10 arrows, what is the probability that her first bullʹs-eye comes on the 5th arrow? Assume each shot is independent of the others. 0.00502 0.00146 0.00707 0.71 0.07369 0.00502 A basketball player has made 65\% of his foul shots during the season.
What is the probability of getting exactly 2 fours?
What is the probability of getting exactly 2 fours? Solution: This is a binomial experiment in which the number of trials is equal to 5, the number of successes is equal to 2, and the probability of success on a single trial is 1/6 or about 0.167. Therefore, the binomial probability is: