How do you calculate coarse aggregate in concrete?

How do you calculate coarse aggregate in concrete?

The quantities of materials for 1 m3 of concrete production can be calculated as follows: The weight of cement required = 7.29 x 50 = 364.5 kg. Weight of fine aggregate (sand) = 1.5 x 364.5 = 546.75 kg. Weight of coarse aggregate = 3 x 364.5 = 1093.5 kg.

How many bags of cement are used in M20 concrete?

8 bag
i.e volume of dry Concrete = 1.54 to 1.57 times Volume of wet concrete. Cement = 8.22 bag. 8 bag of Cement is required for 1cum of concrete work in M20.

What is coarse and fine aggregate?

Fine aggregates generally consist of natural sand or crushed stone with most particles passing through a 3/8-inch sieve. Coarse aggregates are any particles greater than 0.19 inch, but generally range between 3/8 and 1.5 inches in diameter.

How is concrete grade calculated?

Grade of concrete is denoted by prefixing M to the desired strength in MPa. For example, for a grade of concrete with 20 MPa strength, it will be denoted by M20, where M stands for Mix. These grade of concrete is converted into various mix proportions.

What is the cement quantity for M20 concrete mix?

Assuming we need 2 m3of concrete for M20 Concrete Mix, (Mix Ratio, M20 = 1 : 1.5 : 3) Total Part of the Concrete = 1+1.5+3 = 5.5 Parts Therefore, Cement Quantity= (Cement Part / Concrete Parts ) * Concrete Volume                                                  = (1/5.5)* Concrete Volume = (1/5.5)*2 = 0.3636 m3

What is the ratio of cement to fine aggregate?

i.e., Cement: Fine aggregate (Sand) : Coarse Aggregate is in the ratio of 1:2:4 by volume. Cement required = 01 bag = 50 kg ~ 36 liters or 0.036 cum Fine Aggregate required = 2*0.036 ~ 0.07 cum = 0.072*1600 = 115 kg Coarse Aggregate required = 4*0.036 ~ 0.14 cum =0.144*1450 = 209 kg Considering…

How do you calculate cement quantity from concrete volume?

For Cement, Sand and Coarse Aggregate. This is a Volumetric Calculation. Assuming we need 2 m 3 of concrete for M20 Concrete Mix, (Mix Ratio, M20 = 1 : 1.5 : 3) Total Part of the Concrete = 1+1.5+3 = 5.5 Parts. Therefore, Cement Quantity = (Cement Part / Concrete Parts ) * Concrete Volume. = (1/5.5)* Concrete Volume = (1/5.5)*2 = 0.3636 m 3.

What is the volume of sand and aggregate required for concrete?

Since we know the ratio of cement to sand (1:2) and cement to aggregate (1:4) Volume of Sand required would be = 0.035*2 = 0.07 cubic meter (cum) Volume of Aggregate required would be = 0.035*4 = 0.14 cubic meter (cum)