Table of Contents
- 1 How long will it take for the ball to hit the ground?
- 2 How long does it take for the ball to reach its maximum height?
- 3 What is the maximum height of the ball?
- 4 What is the height of the ball after 1.5 seconds?
- 5 How long does it take for a ball to hit the ground?
- 6 How do you calculate the acceleration of a falling ball?
How long will it take for the ball to hit the ground?
To decide where the balls land, we need to determine how long the balls are in the air. Both balls will take 2 seconds to hit the ground.
How long does it take for the ball to reach its maximum height?
1 Expert Answer So the ball reaches its maximum height after 3 seconds.
What is the maximum height of the ball?
Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s. The instantaneous speed of any projectile at its maximum height is zero….Objects Launched Upward.
| Variable | Value |
|---|---|
| v | 0 m/s |
| Δy | FIND |
| a | -9.8 m/s2 |
| t | 0.40 s |
How do you find the maximum height of a ball in physics?
h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
How do you do speed distance time?
To work out speed, divide the distance of the journey by the time it took to travel, so speed = distance divided by time. To calculate time, divide distance by speed. To get the distance, multiply speed by time. You may see these equations simplified as s=d/t, where s is speed, d is distance, and t is time.
What is the height of the ball after 1.5 seconds?
Each point on the graph tells us the height of the ball some number of seconds after it is thrown. The vertex, (1.5, 40), tells us that it takes 1.5 seconds for the ball to reach its maximum height of 40 feet.
How long does it take for a ball to hit the ground?
(a) Since the initial velocity was 0 m/s, the formula becomes s = 1/2 at^2. So it takes approximately 3 seconds for the ball to reach the surface of the earth (neglecting air resistance). A ball is dropped from 10.0m. How long does it take to hit the ground?
How do you calculate the acceleration of a falling ball?
Using the formula s = ut + (at^2)/2, where s = distance, u = inital velocity, t = time, a=acceleration (due to gravity in this case) A ball is dropped from 10.0m.
How do you find the direction of velocity of a ball?
If it is a two-dimensional problem – that is, the ball is tossed at an angle from some height, then one needs to know both the horizontal speed when it hits the ground (hint: same as the initial horizontal speed) and the vertical speed as it hits the ground. Those two components will yield the velocity – that is the speed and direction.
What is the square root of 10/49 when a ball is dropped?
A ball is dropped from a height of 1m. How long will it take for the ball to reach the ground and with what speed does it hit the ground? Lead the way to more purchases. Create unique paths and experiences to lead prospects to purchases with Customer Journey Builder. H= (1/2)gt^2. Using H= 1m Hence, t= square root of 10/49 = 0.45 seconds (approx.)