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Can I pass a Unique_ptr to a function?

Posted on March 29, 2021 by Author

Table of Contents

  • 1 Can I pass a Unique_ptr to a function?
  • 2 Can you dereference a Unique_ptr?
  • 3 Is Unique_ptr initialize to null?
  • 4 How do you create a smart pointer in C++?
  • 5 Should you pass a shared pointer by reference?
  • 6 Should you pass smart pointers by reference?
  • 7 How do you pass a unique_ptr to a function?
  • 8 How do I copy a unique_ptr in C++?

Can I pass a Unique_ptr to a function?

Because the unique pointer does not have a copy constructor. Hence you cannot pass it by value, because passing by value requires making a copy.

Can you dereference a Unique_ptr?

The unique_ptr shall not be empty (i.e., its stored pointer shall not be a null pointer) in order to be dereferenciable. This can easily be checked by casting the unique_ptr object to bool (see unique_ptr::operator bool).

How do I pass a shared pointer?

You can pass a shared_ptr to another function in the following ways:

  1. Pass the shared_ptr by value.
  2. Pass the shared_ptr by reference or const reference.
  3. Pass the underlying pointer or a reference to the underlying object.

What is std :: Unique_ptr?

std::unique_ptr is a smart pointer that owns and manages another object through a pointer and disposes of that object when the unique_ptr goes out of scope. The object is disposed of, using the associated deleter when either of the following happens: the managing unique_ptr object is destroyed.

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Is Unique_ptr initialize to null?

Constructs a unique_ptr object, depending on the signature used: default constructor (1), and (2) The object is empty (owns nothing), with value-initialized stored pointer and stored deleter….std::unique_ptr::unique_ptr.

default (1) constexpr unique_ptr() noexcept;
move (6) unique_ptr (unique_ptr&& x) noexcept;

How do you create a smart pointer in C++?

Declare the smart pointer as an automatic (local) variable. (Do not use the new or malloc expression on the smart pointer itself.) In the type parameter, specify the pointed-to type of the encapsulated pointer. Pass a raw pointer to a new -ed object in the smart pointer constructor.

Do you need to delete a Unique_ptr?

An explicit delete for a unique_ptr would be reset() . But do remember that unique_ptr are there so that you don’t have to manage directly the memory they hold. That is, you should know that a unique_ptr will safely delete its underlying raw pointer once it goes out of scope.

Should I use Unique_ptr?

When to use unique_ptr? Use unique_ptr when you want to have single ownership(Exclusive) of the resource. Only one unique_ptr can point to one resource. Since there can be one unique_ptr for single resource its not possible to copy one unique_ptr to another.

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Should you pass a shared pointer by reference?

In general, you should pass the shared pointer as a straight copy. This gives it its intended semantics: Every scope that contains a copy of the shared pointer keeps the object alive by virtue of its “share” in the ownership.

Should you pass smart pointers by reference?

It’s ok to pass a smart pointer by reference, except if it’s to a constructor. In a constructor, it’s possible to store a reference to the original object, which violates the contract of the smart pointers. You would likely get memory corruption if you did that.

Do I need to delete Unique_ptr?

Does Unique_ptr delete itself?

unique_ptr objects automatically delete the object they manage (using a deleter) as soon as they themselves are destroyed, or as soon as their value changes either by an assignment operation or by an explicit call to unique_ptr::reset.

How do you pass a unique_ptr to a function?

(C) By const l-value reference: If you mean for a function to simply use the unique_ptr for the duration of that function’s execution, take it by const&. Alternatively, pass a & or const& to the actual type pointed to, rather than using a unique_ptr.

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How do I copy a unique_ptr in C++?

You cannot copy a unique_ptr. You can only move it. The proper way to do this is with the std::move standard library function. If you take a unique_ptr by value, you can move from it freely.

How do I pass a raw pointer to myfunc?

If the lifetime of the object is guaranteed to exist over the lifetime of the call to MyFunc, just pass a raw pointer via ptr.get (). Why can I not pass a unique_ptr into a function?

Why does unique_ptr have a move constructor but no copy constructor?

You cannot do that because unique_ptr has a move constructor but not a copy constructor. According to the standard, when a move constructor is defined but a copy constructor is not defined, the copy constructor is deleted. 7 If the class definition does not explicitly declare a copy constructor, one is declared implicitly.

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