Table of Contents
- 1 What is the last term in AP 5 7 9 upto 21 terms?
- 2 What is the sum to n terms of 3 5 7 9?
- 3 How many terms of the ap3 5 7 9 must be added to get the sum 120?
- 4 How many terms of an A.P. 5 7 9 must be added to get the sum 1020?
- 5 What is the sum of first n terms of an AP a 3a 5a?
- 6 What is the common difference of the arithmetic sequence 5/9/13 17 21?
- 7 How do you find the sum of n terms in series?
- 8 What is the sum of 21st to the 50th term inclusive?
- 9 How do you find the common difference of a series?
What is the last term in AP 5 7 9 upto 21 terms?
Therefore last term or the 21st term of the given AP is 45.
What is the sum to n terms of 3 5 7 9?
We have found the sum of n terms of the series 1, 3, 5, 7, …… is n2. ∴ The sum of series 1, 3, 5, 7, 9,…… up to n terms is n2.
What is the formula of last term of AP?
Formula Lists
| General Form of AP | a, a + d, a + 2d, a + 3d, . . . |
|---|---|
| The nth term of AP | an = a + (n – 1) × d |
| Sum of n terms in AP | S = n/2[2a + (n − 1) × d] |
| Sum of all terms in a finite AP with the last term as ‘l’ | n/2(a + l) |
How many terms of the ap3 5 7 9 must be added to get the sum 120?
thus there are 10 terms of the given AP must be added to get sum 120.
How many terms of an A.P. 5 7 9 must be added to get the sum 1020?
The number of terms can be added = 10 – 4 = 6 terms.
How do I find the last 5th term of AP?
1 Answer
- The given AP is 2, 7, 12., 47.
- Let us re-write the given AP in reverse order i.e. 47, 42, .., 12, 7, 2.
- Now, the 5th term from the end of the given AP is equal to the 5th term from beginning of the AP 47, 42,…. ,12, 7, 2.
- Consider the AP 47, 42,…, 12, 7, 2.
What is the sum of first n terms of an AP a 3a 5a?
The given AP is a, 3a, 5a, The first term is a and the common difference is 2a. The sum of n terms of the given AP is Sn = n/2 (2a+(n−1)2a). The sum of n terms of AP a, 3a, 5a, is an2.
What is the common difference of the arithmetic sequence 5/9/13 17 21?
4
There is a difference of 4 between each consecutive number in the sequence. Therefore, the common difference is 4 .
How do you find the nth term of an end?
Ans: The formula to find the nth term of an AP is an=a+(n–1)d.
How do you find the sum of n terms in series?
For an AP, the sum of the first n terms can be calculated if the first term and the total terms are known. The formula for the arithmetic progression sum is explained below: Consider an AP consisting “n” terms. S = n/2 [2a + (n − 1) × d] This is the AP sum formula to find the sum of n terms in series. Proof: Consider an AP consisting “n” terms
What is the sum of 21st to the 50th term inclusive?
Here, “a” is the first term and “l” is the last term which you want to find and “n” is the number of terms. In this case first term which we want to find is 21st so So -2205 is the sum of 21st to the 50th term inclusive. What is Calculatored’s Arithmetic Sequence Calculator?
How do you find the 9th term of a geometric sequence?
The nth term of the geometric sequence is denoted by the term Tn and is given by T n = ar (n-1) where a is the first term and r is the common ratio. Here a = 1, r = 4 and n = 9 So, 9th term is can be calculated as T9 = 1* (4)(9-1) = 4 8 = 65536.
How do you find the common difference of a series?
In this progression, for a given series, the terms used are the first term, the common difference between the two terms and nth term. Suppose, a1, a2, a3, ……………., an is an AP, then; the common difference “ d ” can be obtained as; d = a2 – a1 = a3 – a2 = ……. = an – an – 1 Where “d” is a common difference.