Table of Contents
- 1 Which is the correct order of bond dissociation energy for halogens?
- 2 What is the order of bond dissociation energy?
- 3 Which halogen has lowest dissociation energy?
- 4 Which halogen has the lowest bond dissociation enthalpy?
- 5 How should the order of the halogens look like if they follow an increasing electron affinity?
- 6 What is the Order of bond dissociation energy of halogen molecules?
- 7 How does bond dissociation energy change down the group?
Which is the correct order of bond dissociation energy for halogens?
Correct order of bond dissociation enthalpy of halogens is Cl2 > Br2 > F2 > I2.
What is the order of bond dissociation energy?
The bond dissociation energy increases as the difference in the electronegativities of the bonded atoms increases. For example, the bond dissociation energies of carbon–halogen bonds increase in the order C—I < C—Br < C—Cl < C—F. The polarities of the carbon–halogen bond are in the same order.
Which has highest bond dissociation energy in halogens?
It has three lone pairs of electrons in the outermost shell which face a significant amount of repulsion from the adjacent atom. Thus, this repulsion counters the attraction force and hence, weakens the bond. Therefore, the halogen with the highest bond energy to be option (B)- $C{{l}_{2}}$.
What is the order of electron affinity of halogens?
Therefore, the correct order of electron affinity is Cl > F > Br. Hence, option C is the required answer.
Which halogen has lowest dissociation energy?
Among the halogens, why is it that the fluorine has the lowest bond dissociation enthalpy, considering the fact that fluorine is the smallest and the internuclear distance between the fluorine molecule is least and 2p−2p overlap should also very very strong ,the bond dissociation enthalpy should have been very high but …
Which halogen has the lowest bond dissociation enthalpy?
What is the correct order of reactivity of halogens with alkenes?
F>Cl.
What is the reactivity order of halogens towards substitution in alkanes?
The reactivity order of halogenation of alkanes is F2>Cl2>Br2>I2 .
How should the order of the halogens look like if they follow an increasing electron affinity?
F.
What is the Order of bond dissociation energy of halogen molecules?
Bond dissociation energy of halogen family decreases down the group as the size of atom increases. The decreasing order for the bond dissociation enthalpy of halogen molecules is C l2 57 kcal/mol> Br2 45.5 kcal/mol > F 2
Why is the dissociation energy of F less than Br?
In the halogen family,size of F is very small, so it faces a strong electronic repulsion between its electrons , which makes it bong weak thus reducing its dissociation energy. (the effect is so strong that it’s dissociation energy is less than Br). Well, bond dissociation energy refers to the energy required to break bond between 2 atoms.
Which is expected to have the highest bond dissociation enthalpy?
F2 is expected to have highest bond dissociation enthalpy but it is Cl2…. the correct decreasing order is Cl2>Br2>F2>I2 is is so because fluorine atom has very small size due to which there is a high inter electronic repulsion between two fluorine atoms….so the bond between two fluorine gets weaker amd need less energy
How does bond dissociation energy change down the group?
Well, bond dissociation energy refers to the energy required to break bond between 2 atoms. Its value depends on the strength of the bond. (more strong bond requires high energy to break).As size of atom increases, its bond strength and dissociation energy decreases . So dissociation energy decreases down the group as size increases.