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How do you add two 16-bit numbers in assembly language?

Posted on May 1, 2021 by Author

Table of Contents

  • 1 How do you add two 16-bit numbers in assembly language?
  • 2 When two 16-bit numbers are multiplied in 8086 the result is stored in?
  • 3 How can I add two 16 bit numbers in 8086?
  • 4 What are 16-bit numbers?
  • 5 How to multiply two 8 bit numbers using add and shift method?

How do you add two 16-bit numbers in assembly language?

Algorithm to Add Two 16 Bit Numbers

  1. Step I : Initialize the data segment.
  2. Step II : Get the first number in AX register.
  3. Step III : Get the second number in BX register.
  4. Step IV : Add the two numbers.
  5. Step V : Display the result.

Do programs multiply 2 16-bit numbers?

In this program we will see how to multiply two 16-bit numbers….Input.

Address Data
3000 AD
3001 BC
3002 2D
3003 FE

When we multiply 16-bit number by 16-bit number then the result generated is of size bit?

A 16-bit value multiplied by another 16-bit value results in a 32-bit value (16 + 16), etc. For the sake of example, let’s multiply 25,136 by 17,198. The answer is 432,288,928.

When two 16-bit numbers are multiplied in 8086 the result is stored in?

Problem – Write a program to multiply two 16-bit numbers where starting address is 2000 and the numbers are at 3000 and 3002 memory address and store result into 3004 and 3006 memory address.

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How do you do a 16-bit addition?

Algorithm –

  1. Load both the lower and the higher bits of first number at once.
  2. Copy the first number to another register pair.
  3. Load both the lower and the higher bits of second number at once.
  4. Add both the register pairs and store the result in a memory location.

When 2 16 bit numbers are multiplies how the result is stored?

The multiplication of the two 16 bit numbers may result into a 32 bit number. So result is stored in the DX and AX register. The MSB of result is stored in the DX register and LSB of result in AX register.

How can I add two 16 bit numbers in 8086?

Algorithm –

  1. Load 0000H into CX register (for carry)
  2. Load the data into AX(accumulator) from memory 3000.
  3. Load the data into BX register from memory 3002.
  4. Add BX with Accumulator AX.
  5. Jump if no carry.
  6. Increment CX by 1.
  7. Move data from AX(accumulator) to memory 3004.
  8. Move data from CX register to memory 3006.
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How can I add two 16-bit numbers in 8051?

THEORY. As there is only one 16-bit Register in 89C51, 16-bit addition is performed by using ADDC instruction twice, i.e. adding LSD first and MSD next. DATAM1 – 12; DATAM2 = 56.

Where is the result of 16 bit multiplication stored?

What are 16-bit numbers?

A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.

What is a 16-bit int?

Integer, 16 Bit: Signed Integers ranging from -32768 to +32767. Integer, 16 bit data type is used for numerical tags where variables have the potential for negative or positive values. Integer, 16 Bit Unsigned: Unsigned whole or natural numbers ranging from 0 to +65535.

How to multiply two 8 bit numbers in assembly language?

Write a program to Multiply Two 8 Bit Numbers in assembly language . Program should load first number and second number in registers AL and BL registers . Then it should implement some logic for multiplication of two numbers . Consider that a byte of data is present in the AL register and second byte of data is present in the BL register.

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How to multiply two 8 bit numbers using add and shift method?

Write a program to Multiply Two 8 Bit Numbers using Add and Shift Method in Assembly language .Program should take first and second numbers as input to the program . Now it should implement certain logic to multiply 8 bit Numbers using Add and Shift Method .

How to multiply the contents of two registers using Mul?

We have to multiply the byte in AL with the byte in BL. Using MUL instruction, multiply the contents of two registers. The multiplication of two 8 bit numbers may result into a 16 bit number. So result is stored in AX register. The MSB is stored in AH and LSB in AL.

How can we do multiplication in 8086 microprocessor?

We can do multiplication in 8086 with MUL instruction. For 16-bit data the result may exceed the range, the higher order 16-bit values are stored at DX register. …

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