Table of Contents
- 1 How do you convert a sorted list to a binary tree?
- 2 How will you create a binary search tree using linked list?
- 3 How do you convert a sorted list to a binary search tree in Python?
- 4 How do you convert a list into a tree in Python?
- 5 How do you traverse through a doubly linked list?
- 6 How do you find a doubly linked list?
- 7 How do you convert a binary tree to a linked list?
- 8 Is there an O(n) solution for a BST?
How do you convert a sorted list to a binary tree?
A sorted linked list is used to construct a binary tree from the leaves to the root. The idea is to insert nodes in a binary tree in the same order as they appear in the linked list so that the tree can be constructed with the time complexity of O ( n ) O(n) O(n).
How will you create a binary search tree using linked list?
Algorithm
- Define Node class which has three attributes namely: data left and right.
- When a node is created, data will pass to data attribute of the node and both left and right will be set to null.
- Define another class which has an attribute root.
- insert() will add a new node to the tree:
Can you binary search a doubly linked list?
1 Answer. It’s technically correct to say that the runtime of binary search on a doubly-linked list is O(n log n), but that’s not a tight upper bound. Using a slightly better implementation of binary search and a more clever analysis, it’s possible to get binary search to run in time O(n).
How do you convert a sorted list to a binary search tree in Python?
Convert Sorted Array to Binary Search Tree in Python
- If A is empty, then return Null.
- find the mid element, and make it root.
- Divide the array into two sub-arrays, left part of the mid element, and right part of the mid element.
- recursively perform the same task for the left subarray and right subarray.
How do you convert a list into a tree in Python?
Python – Convert a list of lists into tree-like dict
- Using Slicing. We reverse the items in the list aby slicing and then check if the item is present in the list.
- Example.
- Output.
- Using reduce and getitem.
- Example.
- Output.
How do you add two binary trees?
Given two binary trees. We need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the non-null node will be used as the node of new tree.
How do you traverse through a doubly linked list?
Algorithm
- Step 1: IF HEAD == NULL.
- Step 2: Set PTR = HEAD.
- Step 3: Repeat step 4 and 5 while PTR != NULL.
- Step 4: Write PTR → data.
- Step 5: PTR = PTR → next.
- Step 6: Exit.
How do you find a doubly linked list?
Searching for a specific node in Doubly Linked List
- Traverse the list until the pointer ptr becomes null.
- Compare each element of the list with the item which is to be searched.
- If the item matched with any node value then the location of that value I will be returned from the function else NULL is returned.
Is linked list binary search tree?
In computer science, a linked list is one of the fundamental data structures, and can be used to implement other data structures. So a Binary Search tree is an abstract concept that may be implemented with a linked list or an array. While the linked list is a fundamental data structure.
How do you convert a binary tree to a linked list?
Transformation between Binary Tree and Linked Lists. Given a Binary Tree (or BST). 1. Flatten the BT into a single link in the order of inorder traversal. 2. Flatten the BT into a single link in the order of preorder traversal. 3. Flatten the BST to sorted single linked list. 4.
Is there an O(n) solution for a BST?
Yes there is O(n) solution. Note that an in-order traversalon a BST, is iterating the elements in the desired order, so just do an inorder traversal on an initially empty tree of size n, and fill it with elements in the list. [The i’th element you insert to the tree in your traversal, is the i’th element in the list].
How to make half of a linked list into a root?
1) Get the Middle of the linked list and make it root. 2) Recursively do same for left half and right half. a) Get the middle of left half and make it left child of the root created in step 1. b) Get the middle of right half and make it right child of the root created in step 1.