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How do you draw an equilateral triangle with the perimeter of 10 cm?

Posted on November 5, 2019 by Author

Table of Contents

  • 1 How do you draw an equilateral triangle with the perimeter of 10 cm?
  • 2 How do you draw the perimeter of a equilateral triangle?
  • 3 How do you draw a perimeter of a triangle?
  • 4 How do you draw an equilateral triangle with the perimeter of 13 cm?
  • 5 How do you construct a triangle given the perimeter and ratio?
  • 6 How do you construct an equilateral triangle with altitude 4 cm?

How do you draw an equilateral triangle with the perimeter of 10 cm?

Answer: Draw a slanted line AC of length 6cm from A. Mark the points M and N such that they divides AC into three equal parts of 2cms each. Join the line BC.

How do you draw the perimeter of a equilateral triangle?

  1. Draw a line AB of 15 cm.
  2. At point A draw an angle CAB of 600
  3. At point B draw an angle DBA of 600
  4. Draw the angle bisector of ∠CAB and ∠DBA, both the angle bisector intersect each other at P.
  5. Draw the perpendicular bisector of AP and BP, it intesect AB at Q and R respectively.
  6. Join PQ and PR.
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What is the perimeter of a 10cm triangle?

Solution: Perimeter of the triangle is the sum of the lengths of its sides. Thus, perimeter = 10 cm. 6.

How do you draw a perimeter of a triangle?

Steps of Construction: Step 1: Draw a line segment XY such that XY = AB + BC + CA (i.e. perimeter of triangle ABC) and draw the angle lines at X and Y such that ∠LXY = ∠B and ∠MYX = ∠C. Step 2: Draw the angle bisectors of ∠LXY and ∠MYX and let them meet at A.

How do you draw an equilateral triangle with the perimeter of 13 cm?

Steps of Construction:

  1. Draw B’C’ = 13 cm.
  2. Then divide , B’C’ in the ratio 3:4:5.
  3. B’B : BC : CC’ = 3:4:5 ( by similarity of triangles)
  4. Now, construct AB = B’B.
  5. Construct AC = CC’
  6. Hence AB: BC : AC = 3:4:5.
  7. Hence , Triangle ABC is the required triangle.
  8. Here, AB = 13/4 cm, BC = 13/3 cm & AC = 65/12 cm.

How do you construct an equilateral triangle each of whose altitude measures 5.4 cm?

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1 Answer

  1. Steps of Construction:
  2. Construct a line XY.
  3. Mark a point P on the line XY.
  4. From the point P, construct PQ perpendicular to XY.
  5. From the point P, mark the point PA = 5.4 cm, which cuts the line PQ at the point A.
  6. Draw ∠PAB = 30o and ∠PAC = 30o which meets the line XY at the points B and C.

How do you construct a triangle given the perimeter and ratio?

Constructing a Triangle with a given perimeter in the ratio 2:3:4

  1. Draw a line at any angle from Point A or B (it doesn’t matter which one choose) any length, represented by the green line above.
  2. Mark off nine steps with your compass, using the same radius.
  3. Join the ninth arc back to point B.

How do you construct an equilateral triangle with altitude 4 cm?

Using a protractor, draw an angle of 70o and bisect it. Construct an angle of 45o at the initial point of a given line segment. Draw a line segment of length 5.8cm. Bisect it and measure the length of each part.

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