How do you find the coordinates of a curve?
Find the point(s) where the curve meets the axes Substitute x = 0 in the curve’s equation to find the y coordinate of the point where the curve meets the y axis. Substitute y = 0 in the curve’s equation. If possible, solve the equation to find the x coordinate(s) of the point(s) where the curve meets the x axis.
How do you find the coordinates of a tangent to a curve?
In order to find the equation of a tangent, we:
- Differentiate the equation of the curve.
- Substitute the value into the differentiated equation to find the gradient.
- Substitute the value into the original equation of the curve to find the y-coordinate.
- Substitute your point on the line and the gradient into.
At what point on the curve y 3x x² the slope is?
Answer: At (4, 0) point on a curve y = 3x – x² the slope is -5.
At what point on the curve y x 3 3x are the values of Y and Y equal?
1 Answer. Hi, If your equation is y=x^3+3x then at the point (1,4) y’=y”.
For which value of M is the line y MX 1?
The equation of the tangent to the given curve is y = mx + 1. Now, substituting y = mx + 1 in y2 = 4x, we get: Hence, the required value of m is 1.
How to find the coordinates of each point on the curve?
How to find the coordinates of each point on the curve where the tangent line is vertical? . We evaluate the derivative of the function at the point of tangency to find m = the slope of the tangent line at that point. m = ± ∞ means the tangent line is vertical at that point.
How many y-coordinates are there for each value of X?
Since we found two values of x, in step 2, there are two y -coordinates to calculate, one for each value of x . We can see quite clearly that the stationary point at (− 2, − 4) is a local maximum and the stationary point at (2, 4) is a local minimum .
How do you find the Y-coordinates of stationary points?
Doing this, we get (x + 3) (x – 1) = 0 Leaving x=-3 or x=1 Finally, substitute these values into y = x^3 + 3x^2 -9x -4 and this will give you the y-coordinates to the stationary points. The final answers are therefore (-3,23) and (1,-9) Need help with Maths?
How many stationary points does the curve y = x2 – 4x + 5 have?
We can therefore state that the curve y = x2 − 4x + 5 has one stationary point with coordinates (2, 1) . This result is confirmed, using our graphical calculator and looking at the curve y = x2 − 4x + 5 : We can see quite clearly that the curve has a global minimum point, which is a stationary point, at (2, 1) .