Table of Contents
- 1 How do you find the equivalent weight of an acid medium?
- 2 What is equivalent weight of potassium permanganate in acidic medium?
- 3 What is the equivalent weight of Na2CO3?
- 4 Which of the following acid has the same molecular weight and equivalent weight?
- 5 What is the equivalent weight of acidic salt?
- 6 What is the equivalent weight of KMnO4 in an acidic medium?
- 7 What is the value of Eq wt in an alkaline medium?
How do you find the equivalent weight of an acid medium?
- Answer: (4) Equivalent weight can be calculated by using the formula. Equivalent weight = Molar mass/number of electrons lost or gained (n)
- In acidic medium: MnO4- + 8H +5e– –> Mn2 + 4H2O. Here n = 5.
- In basic medium: MnO4−+ e− → MnO42− Here n = 1.
- In neutral medium: Mno4– + 4H+ + 3e− –> MnO2+ 2H2O. Here n = 3.
What is equivalent weight of potassium permanganate in acidic medium?
31.6 g.
Therefore, equivalent weight in acidic medium = 158/5 = 31.6 g.
What is the equivalent weight of Na2CO3?
106 g/mole
Answer: 53 g/eq The salt Na2CO3 ionizes to produce 2Na+ and CO3-2. So the charge on both ions is 2. Therefore, the molar mass of Na2CO3 is 106 g/mole.
How do you find the equivalent weight of salt?
Equivalent mass of a base = molecular mass of the base/acidity. Equivalent mass of a salt = molecular mass of the salt/total positive valency of metal atoms.
What is meant by equivalent weight of an acid?
For acid–base reactions, the equivalent weight of an acid or base is the mass which supplies or reacts with one mole of hydrogen cations (H + ). For redox reactions, the equivalent weight of each reactant supplies or reacts with one mole of electrons (e−) in a redox reaction.
Which of the following acid has the same molecular weight and equivalent weight?
H2SO4.
What is the equivalent weight of acidic salt?
Equivalent mass of a salt is also that mass of it, which will combine with one gram equivalent of another substance. one gram equivalent of Na2CO3 reacts with 2 gram equivalent of HCl. Hence equivalent mass of Na2CO3 is 106 / 2 = 53.
What is the equivalent weight of KMnO4 in an acidic medium?
As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it’s equivalent weight becomes M/5. (where M is Molar mass of KMnO4.) Since mass of KMnO4 is 158, Equivalent Weight in acidic Medium is 31.4g.
Is KMnO4 a strong oxidising agent?
Answer Wiki. KMnO4 is a strong oxidising agent . In acidic medium, itself reduced to Mn2+ while in basic or neutral medium it reduced to MnO2, logic behind this is very simple , as acidic medium is also called as electron deficient medium .
What is the electron configuration of Mn+2 in KMnO4?
The Mn in KMnO4 exists in +7 state. In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons.
What is the value of Eq wt in an alkaline medium?
In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons. so, eq wt = 158/5 = 31.6 g. In many cases though if it’s written alkaline, it mostly means the neutral one; for the highly alkaline thing, it’ll especially mention it.