How do you prove that a=B=C?

How do you prove that a=B=C?

If a^2+b^2+c^2-ab-bc-ca=0 then prove that a=b=c. – JEE Maths Q&A If a^2+b^2+c^2-ab-bc-ca=0 then prove that a=b=c.

How do you prove that a/p is divisible by C?

$\\begingroup$Nice proof. You don’t actually need to use c/p. You can say that a/p is divisible by c and that’s enough. ie: you use induction on ‘a’ such that b is any integer such that (a,b) = 1, and c is any integer such that a|c and b|c.

How do you do a proof of a vector equation (BXC)?

(BxC) can be evaluated using the matrix of cross product to yield (taking only y nad z components): For simplicity just take one of the components of the resulting vector, say the x component. The resulting solution can be extended to the other two owing to symmetry. Open both sides of the equation as you would in elementary trigonometry proofs.

How do you find the BXC of an equation?

Open both sides of the equation as you would in elementary trigonometry proofs. (BxC) can be evaluated using the matrix of cross product to yield (taking only y nad z components): For simplicity just take one of the components of the resulting vector, say the x component.

https://www.youtube.com/watch?v=EvTz7CVdqH0

How do you find the cosine rule for a right triangle?

Deriving other Laws Using the Cosine Rule. The Pythagorean theorem applies to right triangles, so let γ be a right angle, i.e., γ = π 2. Then by the cosine rule, c2 = a2 +b2 −2abcosγ = a2 +b2 −2abcos π 2 = a2 +b2 −0 = a2 +b2.

How do you find the value of C2 using cosine rule?

Then by the cosine rule, c 2 = a 2 + b 2 − 2 a b cos ⁡ γ = a 2 + b 2 − 2 a b cos ⁡ π 2 = a 2 + b 2 − 0 = a 2 + b 2. = a2 + b2 − 0 = a2 +b2.

How do you calculate B2 from C2?

Then b2 can be calculated as b2 = c2 – a2. Now check if a <= b <= c and b2 calculated in the previous step must be a perfect square. If the above conditions are satisfied then increment the count.

https://www.youtube.com/watch?v=KpNd2GsXw0k