Table of Contents
How do you prove the distributive property?
Let the number A be a multiple of the number C, and let the number B be the same multiple of the number D. Then the sum of A and B will also be that multiple of the sum of C and D. For, since A is the same multiple of C that B is of D, there are as many numbers in A equal to C as there are in B equal to D.
How do you prove a set using a Venn diagram?
Proving Distributive law of sets by Venn Diagram
- We have to prove. A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
- Distributive law is also. A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C ) this can also be proved in the same way. Proof using examples is done here.
How do you use distributive property in sets?
Example 1 : Let A = {0, 1, 2, 3, 4}, B = {1, – 2, 3, 4, 5, 6} and C = {2, 4, 6, 7}. (i) Show that A U (B n C) = (A U B) n (A U C) (ii) Verify using Venn diagram.
How do you prove the distributive law property of sets theory?
If x ∈ (A ∩ B) ∪ (A ∩ C) then x ∈ (A ∩ B) or x ∈ (A ∩ C). Hence, distributive law property of sets theory has been proved. Distributive Law states that, the sum and product remain the same value even when the order of the elements is altered.
What is distributive law?
Distributive Law states that, the sum and product remain the same value even when the order of the elements is altered. First law states that taking the union of a set to the intersection of two other sets is the same as taking the union of the original set and both the other two sets separately, and then taking the intersection of the results.
Is there a real proof of the first distribution law?
Here is a ‘real’ proof of the first distribution law: If x is in A union ( B intersect C) then x is either in A or in ( B and C ). Therefore, we have to consider two cases: If x is in A, then x is also in ( A union B) as well as in ( A union C ).
What is the formula for taking the Union of two sets?
A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C) First law states that taking the union of a set to the intersection of two other sets is the same as taking the union of the original set and both the other two sets separately, and then taking the intersection of the results.