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How does the radius of circular path of a charged particle moving in a uniform magnetic field depends upon its momentum and charge?

Posted on July 28, 2021 by Author

Table of Contents [hide]

  • 1 How does the radius of circular path of a charged particle moving in a uniform magnetic field depends upon its momentum and charge?
  • 2 How do you find the radius of a magnetic field?
  • 3 Why do charged particles move in a circular path?
  • 4 How do you find the radius of a circle in circular motion?
  • 5 What is radius in circular motion?
  • 6 What determines the radius of a particle in a circular orbit?
  • 7 How do you find the radius of a magnetic orbit?
  • 8 What is the radius of a charged particle in a magnetic field?

How does the radius of circular path of a charged particle moving in a uniform magnetic field depends upon its momentum and charge?

The radius of the orbit depends on the charge and velocity of the particle as well as the strength of the magnetic field. The acceleration of a particle in a circular orbit is: Thus the radius of the orbit depends on the particle’s momentum, mv, and the product of the charge and strength of the magnetic field.

How do you find the radius of a magnetic field?

We can find the radius of curvature r directly from the equation r=mvqB r = m v q B , since all other quantities in it are given or known.

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What is the formula of the radius of a circular path in which the charged particle moving in a magnetic field and the formula of the time period also?

Magnetic force →F=q→v×→B. This force acts as a centripetal force and produces a circular motion (as per the Fleming’s Left Hand Rule). Therefore, radius of the circular path r∝mq for a given uniform speed and magnetic field.

Why do charged particles move in a circular path?

Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

How do you find the radius of a circle in circular motion?

r=mv2Fc. r = m v 2 F c . This implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curve, as in (Figure).

What will be the criteria for a particle to move in circular path?

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For a particle to move in a circular orbit uniformly, centripetal force is required which infact depends upon mass (m), velocity (v), and radius (r) of the circle.

What is radius in circular motion?

Objects moving in circles have a speed which is equal to the distance traveled per time of travel. The distance around a circle is equivalent to a circumference and calculated as 2•pi•R where R is the radius. The time for one revolution around the circle is referred to as the period and denoted by the symbol T.

What determines the radius of a particle in a circular orbit?

The radius of the orbit depends on the charge and velocity of the particle as well as the strength of the magnetic field. The acceleration of a particle in a circular orbit is: Thus the radius of the orbit depends on the particle’s momentum, mv , and the product of the charge and strength of the magnetic field.

How do you find the period of circular motion in a magnetic?

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A magnetic force can supply centripetal force and cause a charged particle to move in a circular path of radius r = mv qB. r = m v q B. The period of circular motion for a charged particle moving in a magnetic field perpendicular to the plane of motion is T = 2πm qB. T = 2 π m q B.

How do you find the radius of a magnetic orbit?

The radius of the orbit depends on the charge and velocity of the particle as well as the strength of the magnetic field. Using F = ma, one obtains: Thus the radius of the orbit depends on the particle’s momentum, mv, and the product of the charge and strength of the magnetic field.

What is the radius of a charged particle in a magnetic field?

A charged particle is moving on circular  path with velocity v in a uniform magnetic field B, if the velocity of the charged particle is doubled and strength of magnetic field is halved, then radius becomes : A 8 times B 4 times C 2 times D

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