Table of Contents
How many grams of sodium chloride are required make 500 mL of normal saline solution?
Answer: 10 mg. Mass of 500 mL NaCl solution is roughly 500 mg, because water density is about 1 mg/ml (so low 2\% NaCl concentration doesn’t make significant difference in density). So as NaCl mass is 2\% of the solution mass – 0,02*500=10mg.
How do you make a 2 NaCl solution?
Procedure
- 0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.
- 0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.
- 2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.
How would you prepare 500ml of a 5M solution of NaCl?
Directions: 1) Mix 146.1 g of NaCl with 450 ml of ddH2O by stirring. 2) Add ddH2O until final volume is 500 ml.
What is a 2\% NaCl solution?
2\% solution: NaCl 20 g, Distilled water 1 liter. 3\% solution: NaCl 30 g, Distilled water 1 liter. Dissolve NaCl in water.
How many grams of sodium chloride are in a 1000 mL bag of 0.9 normal saline?
How many grams of sodium chloride are contained in the bag? 1000 x 0.9 = 900 ÷ 100 = 9 ( 9 g NaCl ) Page 29 4.
How do you make 2M sodium chloride?
Fill a flask with 0.8 liters of water, weigh out the amount of sodium chloride you need, add it to the water and shake until it dissolves. To make a 1M solution, add 58.44 grams of salt; to make a 0.1M solution, add 5.84 grams; to make a 2M solution, add 116.88 grams and so on.
How many grams of NaCl are present in 300 mL of 2\% NaCl solution?
6 g
Hence, 2 \% (m/v) NaCl solution will contain 6 g of NaCl in 300 mL of solution.
How do you make 500ml saline solution?
Put 2 cups (500 ml) of tap water and 1 teaspoon (5 ml) of salt into the pot. Put the lid on. 4. Heat to boiling with the lid on.
How many grams of NaCl will be needed to prepare 500ml solution?
To prepare 0.2M in 100ml we have take 1.1688 gram of NaCl . How many g of NaOH will be needed to prepare 500 ml of 0.4M solution? The Answer is 8 grams of NaOH. Molarity = Mass of solute × 1000/ (Molar mass of solute × Volume of solution in mL). It is given that M=0.4 and V= 500mL.
What is the molarity of NaCl in a 250 mL solution?
A 1 M solution corresponds to 1 mole of the solute (here, sodium chloride, NaCl) in 1 L of solvent (here probably water). Since the question calls for only making 250 mL, or 1/4 of a L, only 1/4 or 0.25 mol will be required.
How much CaCl2 is needed to make a 100ml solution?
For example, to make 100 ml of 0.1 M CaCl 2 solution, use the previous formula to find out how much CaCl 2 you need: Now you can make your solution: dissolve 1.11 g of CaCl 2 in sufficient water to make 100 ml of solution.
How do you calculate the molecular weight of NaCl in water?
Step 1: 1 molar solution of NaCl=58.4 g of NaCl in 1 litre of distilled water. Step 2: 5 molar solution of NaCl= 58.4*5 g of NaCl in 1 litre of distilled water. Step 3: 5 molar solution of NaCl= (58.4*5)/2 g of NaCl in 500 ml of distilled water. This is your final answer. Source for molecular weight: https://www.google.co.in/search?…