How many numbers have the property that the sum of the digits of n and the sum of digits of N 1 are odd numbers?

How many numbers have the property that the sum of the digits of n and the sum of digits of N 1 are odd numbers?

Hence 90 such numbers.

How many numbers have the sum of all the factors equal to the number itself?

Every number is a factor of itself. 1 is a factor of every number. A number for which sum of all its factors is equal to twice the number is called a perfect number.

How do you find the odd and even location of a number?

First, calculate the reverse of the given number. To the reverse number we apply modulus operator and extract its last digit which is actually the first digit of a number so it is odd positioned digit. The next digit will be even positioned digit, and we can take the sum in alternating turns.

How do you find the sum of odd numbers in a number?

Steps

1. Let N be the input number.
2. Initialize sum = 0.
3. Repeat the following steps while N > 0. Set r = N \% 10. We are storing the rightmost digit of N in r. Set N = N / 10. We are removing the rightmost digit of N. If r is odd, set sum = sum + r. If r is even, do nothing.
4. The sum of odd digits is stored in sum.

How do you find the sum of digits?

Sum of digits algorithm

1. Step 1: Get number by user.
2. Step 2: Get the modulus/remainder of the number.
3. Step 3: sum the remainder of the number.
4. Step 4: Divide the number by 10.
5. Step 5: Repeat the step 2 while number is greater than 0.

How do you find how many factors a number has?

How to Find Number of Factors?

1. Find its prime factorization, i.e. express it as the product of primes.
2. Write the prime factorization in the exponent form.
3. Add 1 to each of the exponents.
4. Multiply all the resultant numbers.
5. This product would give the number of factors of the given number.

How do you find the sum of even and odd digits?

The program output is also shown below.

1. #include
2. void main()
3. {
4. int i, num, odd_sum = 0, even_sum = 0;
5. printf(“Enter the value of num\n”);
6. scanf(“\%d”, #);
7. for (i = 1; i <= num; i++)
8. {

How do you find the sum of first n odd natural numbers?

So, we know that the first odd natural number is 1. Also, all the odd terms will form an A.P. with the common difference of 2. Therefore, the sum of first n odd natural numbers is S n = n 2 .

How to find the sum of first n odd natural numbers?

It is noted that the unit’s digit of the square of a natural number is equal to the unit’s digit of the square of the digit at unit’s place of the given natural number. For every natural number n, we can write it as: (n + 1) 2 – n 2 = ( n + 1) + n.. If a number n is squared, it equals the sum of first n odd natural numbers.

What are the properties of even and odd numbers?

Squares of even numbers are even, i.e, (2n) 2 = 4n 2. Squares of odd numbers are odd, i.e, (2n + 1) 2 = 4 (n 2 + n) + 1. Since every odd square is of the form 4n + 1, the odd numbers that are of the form 4n + 3 are not square numbers. Properties of Square Numbers

What is the sum of odd numbers from 1 to infinity?

The sum of odd numbers from 1 to infinity can be found easily, using Arithmetic Progression. As we know, the odd numbers are the numbers which are not divisible by 2. They are 1,3,5,7,9,11,13,15,17,19 and so on.

What are the odd numbers that are not square numbers?

Squares of odd numbers are odd, i.e, (2n + 1) = 4 (n 2 + n) + 1. Since every odd square is of the form 4n + 1, the odd numbers that are of the form 4n + 3 are not square numbers. A number with 2, 3, 7 or 8 at unit’s place should never be a perfect square. In other words, none of the square numbers ends in 2, 3, 7 or 8.