How many ways can 4 girls and 5 boys be arranged in a row?

How many ways can 4 girls and 5 boys be arranged in a row?

To do so, we will multiply all the above-calculated values. So, we have =120×15×6×4=43200. Hence, the number of ways to arrange the seating of 5 boys and 4 girls such that two girls are together and other 2 are also together but separate from the first two is 43200, which is option (a).

How many ways can 5 boys and 4 girls be arranged on a bench if there are no restrictions?

=frac 6 * 7 * 5 * 5 * 4 * 3 * 2 * 18 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40.320/1 + 40.320/1 =80.640.

How many ways can you arrange 4 boys 4 girls?

There are 4 boys and 4 girls; they can be permuted among themselves in 8! = 40320 ways.

How many ways can 4 boys and 4 girls be seated at a round table if the girls and boys are to occupy alternate seats?

Thus, there are 4! 3! =144 ways of sitting the girls in which the boys and girls alternate seats.

How many ways can 6 different books be arranged on a shelf?

Therefore, we have 720 ways of arranging 6 books on the shelf.

How many permutations are there?

Permutations differ from combinations, which are selections of some members of a set regardless of order. For example, written as tuples, there are six permutations of the set {1, 2, 3}, namely (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), and (3, 2, 1).

How do you calculate a permutation?

Formula and Calculation of Permutation The formula for a permutation is: P(n,r) = n! / (n-r)! The generalized expression of the formula is, “How many ways can you arrange ‘r’ from a set of ‘n’ if the order matters?” A permutation can be calculated by hand as well, where all the possible permutations are written out.

How many different ways could 5 boys be arranged in a line?

Five boys and-five girls form a line with the boys and girls alternating. Find the number of ways of making the line. In how many different ways could they form a circle such that the boys and girls alternate? 5 boys can be arranged in a line in 5! ways. Now here the boys and girls are alternating.

How many gaps are created when 5 girls stand in row?

If 5 girls stand in a row, 6 gaps are created. But there are 5 boys. Ways of selecting 5 gaps from 6 = 6C5 = 6. Now, boys can change their places in 5! ways & the same thing is true for girls. Total permutations = 6 × 5! × 5!.

How many ways can you arrange 4 girls in a wedding?

The standard way to solve these is to treat the four girls as a single “boy.” That gives you six “boys” in total, which can be arranged 6! = 720 ways. Then, for each of those 720 arrangements, you have the 4! = 24 ways to seat the four girls. 720 x 24 = 17,280.

How many ways can two groups be arranged among themselves?

Answer Wiki. 5 boys together will form Group-1 and 4 girls together will form Group-2. Now, these two groups can be arranged among themselves in (2!) = 2 ways. Now, Group-1 can be formed in (5!) = 120 ways and Group-2 can be formed in (4!) = 24 ways.