How would you find the kth largest element in a binary search tree?

How would you find the kth largest element in a binary search tree?

To find Kth largest element in a Binary search tree, the simplest logic is to do reverse inorder traversal and while doing reverse inorder traversal simply keep a count of number of Nodes visited. When the count becomes equal to k, we stop the traversal and print the data.

Are duplicates allowed in binary search tree?

In a Binary Search Tree (BST), all keys in left subtree of a key must be smaller and all keys in right subtree must be greater. So a Binary Search Tree by definition has distinct keys and duplicates in binary search tree are not allowed.

How do you implement tree mirroring?

Algorithm to create a mirror image of a tree

1. If root is NULL, return NULL.
2. Create a new node and copy the data of root node to new node. Let the name if new node be newNode.
3. Recursively create mirror tree of left and right sub tree. let it be leftMirror and rightMirror.
4. Interchange left and right pointers.

How do you find duplicates in a binary search tree?

A simple solution is to store inorder traversal of given binary tree in an array. Then check if array has duplicates or not. We can avoid the use of array and solve the problem in O(n) time. The idea is to use hashing.

How do you find the kth smallest element without sorting?

Solution Steps

1. Partition the array A[left .. right] into two subarrays A[left ..
2. Computes the number of elements in the subarray A[left .. pos] i.e. count = pos – left + 1.
3. if (count == K), then A[pos] is the Kth smallest element.
4. Otherwise determines in which of the two subarrays A[left .. pos-1] and A[pos + 1 ..

How to find the kth element of a binary search tree?

You can use iterative inorder traversal: http://en.wikipedia.org/wiki/Tree_traversal#Iterative_Traversal with a simple check for kth element after poping a node out of the stack. Given just a plain binary search tree, about all you can do is start from the smallest, and traverse upward to find the right node.

How to find k’th largest element in BST?

K’th Largest Element in BST when modification to BST is not allowed. Given a Binary Search Tree (BST) and a positive integer k, find the k’th largest element in the Binary Search Tree. For example, in the following BST, if k = 3, then output should be 14, and if k = 5, then output should be 10. We have discussed two methods in this post.

How do you find the kth smallest node in a tree?

Assume that the root is having ‘lCount’ nodes in its left subtree. If K = lCount + 1, root is K-th node. If K < lCount + 1, we will continue our search (recursion) for the Kth smallest element in the left subtree of root. If K > lCount + 1, we continue our search in the right subtree for the (K – lCount – 1)-th smallest element.

How to find the k-th smallest element in the left subtree?

Since we need K-th smallest element, we can maintain number of elements of left subtree in every node. Assume that the root is having N nodes in its left subtree. If K = N + 1, root is K-th node. If K < N, we will continue our search (recursion) for the Kth smallest element in the left subtree of root.