Table of Contents
What is equivalent weight of CuSO4 5H2O?
Thus, the equivalent weight of CuSO4. 5H2O is half of its molecular weight. If the molecular weight is 249.7g/mol, the equivalent weight is 124.9.
What is the equivalent mass of CuSO4?
For ionic salts we take the amount of charge present on an ion (cation or anion) to be the n factor, we have equivalent mass of CuSO4 as 159.609/2 = 79.804 gm/mol.
What is the equivalent weight of Na2SO4?
Question: The equivalent weight of Na2SO4 are? (Theanswer is 71 g/Equiv) Could you please explain this problem indetail I have hard time with understanding the valence rules andwhat to divide, thanks.
How do you calculate the normality of CuSO4?
We can calculate the normality of the solution using the given mass and molar mass of copper sulfate and the number of equivalence of the solution. We know that the molar mass of copper sulfate is $159g/mol$. So, we can write the normality of the solution as $\dfrac{{\dfrac{{2.54}}{1}}}{{\dfrac{{159}}{2}}}$.
How do you calculate the normality of cuso4?
How do you find the equivalent weight of K2Cr2O7?
Calculate equivalent weight of K2Cr2O7 in acidic medium. = 294 g/mol. Now, putting these values in above formula of equivalent weight: \[Equivalent{\text{ }}weight = \dfrac{{294}}{6} = 49g/eq\]. Hence, the equivalent weight of ${K_2}C{r_2}{O_7}$ in acidic medium will be 49g/eq.
What is the meaning of 5H2O?
ItCuSO4.5H2O. In this Compound the water is present as water of Crystallisation. ie.,the H2O Molecule is not present in the crystalline structure of Copper Sulphate. Similarly certain double salts like, Mohr’s Salt which is nothing but Ferrous Ammonium Sulphate .
How do you determine normality?
Normality Formula
- Normality = Number of gram equivalents × [volume of solution in litres]-1
- Number of gram equivalents = weight of solute × [Equivalent weight of solute]-1
- N = Weight of Solute (gram) × [Equivalent weight × Volume (L)]
- N = Molarity × Molar mass × [Equivalent mass]-1