What is projectile find the time of flight horizontal range and maximum height of horizontal projectile?

What is projectile find the time of flight horizontal range and maximum height of horizontal projectile?

Ans: Maximum height reached = 30.6 m, time of ascent = 2.5 s, time of flight = 5s, Horizontal range = 212.2 m, Direction of velocity after 1 s is 19o6′ with horizontal. Given: velocity of projection = vo = 60 m/s, Angle of projection = θ = 30o, g = 9.8 m/s2.

What is projectile motion derive the expression for time of flight maximum height and horizontal range?

Time of maximum height is the time when the object attains the maximum height and is given by t=usinθg. Time of flight is the total time taken by the object to cover the total horizontal distance or in other words the time till when the object is in air and is given by T=2usinθg.

How do we calculate the range time of flight and maximum heights of projectiles?

To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.

What is the time required by a projectile to reach the maximum height possible?

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance). You have 176 seconds, or 2 minutes and 56 seconds, until the cannonball destroys the cannon that fired it.

What is the formula of maximum horizontal range?

The range R (in the horizontal direction) is given as: R=v0⋅T=v0√2Hg R = v 0 ⋅ T = v 0 2 H g .

What is horizontal range?

The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).

What is Time of Flight in projectile?

The time of flight of a projectile motion is exactly what it sounds like. It is the time from when the object is projected to the time it reaches the surface. The time of flight depends on the initial velocity of the object and the angle of the projection, θ .

How do you find time with maximum height?

Determine the time it takes for the projectile to reach its maximum height. Use the formula (0 – V) / -32.2 ft/s^2 = T where V is the initial vertical velocity found in step 2. In this formula, 0 represents the vertical velocity of the projectile at its peak and -32.2 ft/s^2 represents the acceleration due to gravity.

When is the horizontal range of a projectile maximum?

Thus for a given velocity of projection, the horizontal range is maximum when the angle of projection is 45°. Relation Between Maximum Range and Maximum Height Reached by Projectile: The maximum height reached H by the projectile is given by The horizontal range R of the projectile is given by

What is the velocity of the body projected at 30o with the horizontal?

A body is projected with the velocity of 60 m/s at an angle of 30o with the horizontal. Find a) the maximum height reached by the body, b) the time of flight, c) horizontal range

How do you find the angle of projection of a projectile?

The angle of projection for which the maximum height of the projectile is equal to the horizontal range has to be determined. Let the required angle of projection be A and object is projected at V m/s. The horizontal component of the velocity is V*cos A and the vertical component is V*sin A.

What is the maximum height if the angle of projection is 75?

If the angle of projection is 75.96 degrees the maximum height is equal to the horizontal range. A ball is thrown into the air at an angle of 45 degrees. At what point is the total velocity the greatest?