Table of Contents
- 1 What is the amount of NaCl required to prepare 200mL?
- 2 How do you make 200mL of a 0.1 M solution?
- 3 What is 2 molar solution?
- 4 How do you make 200 ml of a 0.1 M solution of a substance that has a molecular weight of 121.1g Mol?
- 5 What is the mass of NaCl that needed to make 300 ml of 2.0 M NaCl solution?
- 6 How do you calculate the mass of a solution?
What is the amount of NaCl required to prepare 200mL?
Hence 10 grams of NaCl is required to make 200 mL aqueous solution of 5\%(w/v) NaCl. Note: The mass of solute must always be expressed in grams (g) and the volume of the solution (solvent + solute) should be in milliliters (mL).
How do you make 200mL of a 0.1 M solution?
Need 0.1 moles Na2SO4 per 1L solution, or 0.05 moles per 200 mL. Since the molar mass is 142 g/mol, 0.05 moles is 2.84 g. So, weight 2.84 g of Na2SO4, transfer to a measuring cylinder, and add water to make up the total volume of 200 mL.
How is 200mL of 0.3 m NaCl prepared *?
Add 3.51g NaCl to 200mL of deionized water, you’ll end up with 200mL of 0.3M NaCl solution.
How do you find the mass of a NaCl solution?
The molar mass of sodium is 22.990 g/mol. The molar mass of chlorine is 35.45 g/mol. To calculate the molar mass of NaCl, multiply the subscript of each element times its molar mass, then add them together. If there is no subscript, it is understood to be 1 .
What is 2 molar solution?
2 molar solution means 2 M. given moles of solute = 0.5 mole. Volume of solution =moles of soluteM×1000. Volume of solution = 0.52×1000 = 250 mL of solution.
How do you make 200 ml of a 0.1 M solution of a substance that has a molecular weight of 121.1g Mol?
1 Approved Answer Molarity = m*1000/MW*V m =Molarity* MW*V/1000 = 0.1*121.1*200/1000 =2.422…
How do you prepare a 0.3 M solution of NaCl?
For example: Make 250 mL of a 0.30 M NaCl solution. To make the solution we need to calculate the amount of NaCl to dissolve to make 250 mL of solution. The solution is made by adding 4.38 g NaCl to a 250-mL volumetric flask.
How do you make a 0.3 M solution?
A solution 0.3 M contain 0.3 moles/liters thus two liters will contain (0.3) (2) = 0.6 mole. Since number of moles = gr/mw it follows that gr = (moles) (mw) = (0.6)(36) = 21.6 grams. 9.
What is the mass of NaCl that needed to make 300 ml of 2.0 M NaCl solution?
6 g
Hence, 2 \% (m/v) NaCl solution will contain 6 g of NaCl in 300 mL of solution.
How do you calculate the mass of a solution?
Rearranging the equation for concentration allows the mass of solute to be calculated:
- mass of solute in g = concentration in g/dm 3 × volume in dm 3
- A solution of sodium chloride has a concentration of 10 g/dm 3.
- mass of solute in g = concentration in g/dm 3 × volume in dm 3
- = 10 g/dm 3 × 2 dm 3