Table of Contents
- 1 What is the area of a triangle formed by 3x 2y 6?
- 2 How do you find the area of a triangle with coordinates?
- 3 What is axis of coordinate?
- 4 What is the combined equation of the coordinate axes?
- 5 How to find the height of a triangle formed by x+y+6=0?
- 6 What is the x-intercept of a triangle with a right angle?
What is the area of a triangle formed by 3x 2y 6?
The area of the triangle formed by the straight line 3x + 2y = 6 and the co-ordinate axes is. 3 square units. 6 square units.
How do you find the area of a triangle with coordinates?
The formula of area of triangle formula in coordinate geometry the area of triangle in coordinate geometry is: A = (1/2) |x1 1 (y2 2 − y3 3 ) + x2 2 (y3 3 − y1 1 ) + x3 3 (y1 1 − y2 2 )|, where (x1 1 ,y1 1 ),(x2 2 ,y2 2 ), and (x3 3 ,y3 3 ) are the coordinates of vertices of triangle.
Is triangle ABC similar to Pqr?
If AD and PM are altitudes of the two triangles, Hence, PQAB=PMAD.
How is triangle formed?
All triangles are formed by the intersection of three diagonals at three different points. There are five arrangements of three diagonals to consider. We classify them based on the number of distinct diagonal endpoints.
What is axis of coordinate?
Definition of axes of coordinates 1 : two intersecting straight lines used as reference lines in plane Cartesian geometry. 2 : the three straight lines having a common point that are the intersections of the three coordinate planes of reference in three-dimensional Cartesian geometry.
What is the combined equation of the coordinate axes?
x+y=0.
How do you find the area of a triangle?
Find the area of the triangle formed by the line 3x + 4y = 12 and the co – ordinate axes. >> Find the area of the triang… Find the area of the triangle formed by the line 3x+4y=12 and the co-ordinate axes. Given the equation of the straight line is 3x+4y=12.
What is the area of 3x+2y = 6?
The line 3x+2y = 6 intersects the x-axis when y = 0, that is where x =6/3=2. The line intersects the y-axis when x = 0, that is where y = 6/2 = 3. So the two legs of the right angle triangle are 2 and 3, Hence the area is 2*3/2 = 3 sq units.
How to find the height of a triangle formed by x+y+6=0?
Similarly the point of intersection with y axis is (0 -6) . This can be obtained by putting x=0. So the vertices of the triangle formed by the line x+y+6=0 and the coordinate axes are (-6 0) and (0 -6) and (0 0). Here if we take the x intercept as length of the base then y intercept will become the height of the triangle.
What is the x-intercept of a triangle with a right angle?
You are now presented with a right triangle of height 3 and base 2 with the right angle at the origin. The area is (1/2)bh, and thus is 3. Divide by 6 and get x 2 + y 3 = 1 which is the two intercept form, so the x-intercept is 2 and the y-intercept is 3.