What is the charge on the inner surface of the spherical shell?

What is the charge on the inner surface of the spherical shell?

zero
Since the Electric field vanishes everywhere inside the volume of a good conductor, its value is zero everywhere on the Gaussian surface we have considered. So the surface integral is zero. This is the total charge induced on the inner surface.

Why there is no gravitational force inside a spherical shell?

Inside the shell, the net gravitational force is zero. This is because there is no mass inside, the gravitational field is zero, thereby force is zero.

What is the charge on the outer spherical surface?

(B) There can be no net charge inside the conductor, therefore the inner surface of the shell must carry a net charge of -Q1, and the outer surface must carry the charge +Q1 + Q2, so that the net charge on the shell equals Q2. Question 3. A solid conducting sphere is concentric with a thin conducting shell, as shown.

Why the charge is only on the surface of the sphere?

The charge distributes uniformly on the surface of a spherical conductor (which is far from any other body) due to the spherical symmetry of the problem. There is no reason why it should accumulate at any location of the surface more than at any other location. Therefore it is distributed uniformly.

Where is charge located on a sphere?

So we can say: The electric field is zero inside a conducting sphere. The electric field outside the sphere is given by: E = kQ/r2, just like a point charge. The excess charge is located on the outside of the sphere.

What is the charge on the inner surface of the smaller spherical conducting shell under static conditions the charge on a conductor?

What is the charge on the inner surface of the smaller spherical conducting shell, 1.2 cm from the 2 pC point charge? Under static conditions, the charge on a conductor resides on the surface of the conductor. Correct answer: −2 pC.

What is gravitational field inside a spherical shell?

The gravitational field inside a hollow spherical shell is zero, as potential is constant inside.

What happens to the gravitational potential at the Centre of the uniform spherical shell?

Answer: the gravitational potential at the centre of a uniform spherical shell is inversely proportional to the radius of the shell with a negative sign. When a uniform spherical shell gradually shrinks, the gravitational potential at the centre decreases (because of the negative sign in the formula of potential).

Why is charge always on the outer surface of the conductor?

The electric field inside the conductor is zero. In case of conductors, this electric field is always equal to that of the external electric field and hence the external field is neutralized. Hence all the charges move as far away as possible, i.e. on the surface of the conductor.

Why is charge on a conductor on the surface?

In all conductors, charges reside on the surface. The reason for this is that conductors have free electrons, that is, the electrons are loosely attached to the nucleus of the atoms in the conductors.

Why does charge remains on the surface of a conductor?

What is the magnitude of electric field inside a charged spherical shell?

It would experience no net force inside shell. It is free to move. Since there are no charges inside a charged spherical shell . This means the net charge is equal to zero. So magnitude of electric field E =0. So there is no net force. So magnitude of net force =0.

What is the charge on the outer surface of the shell?

A point charge q is placed at the center of the shell and another charge q1 is placed outside it as shown in the figure .All the three charges are positive. According to Gauss Law , charge q will induce charge –q on the inner surface of the shell ,so that charge on the outer surface of the shell is Q+q .

Why does the central charge experience zero force from the shell?

The shell experiences zero net force from the central charge, so the central charge experiences zero force from the shell. It is an other thing that you can replace the metal shell by the surface charge density on both surfaces, as if the metal was not present, when calculating electric field.

Why is there no net electric field in a spherical shell?

If the charges on the spherical shell are uniformly distributed, then there will be no net electric field due to the shell anywhere within the shell.