What is the probability of a jack in a deck of cards?
Find the probability of: In a playing card there are 52 cards. Number of favourable outcomes i.e. ‘2’ of spades is 1 out of 52 cards. Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards.
How many cards are there in a deck of cards?
There are 52 cards in a standard deck of cards There are 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.) There are 4 suits (Clubs, Hearts, Diamonds, and Spades) and there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red)
How many face cards are there in a deck of 52 cards?
The card in each suit, are ace, king, queen, jack or knaves, 10, 9, 8, 7, 6, 5, 4, 3 and 2. King, Queen and Jack (or Knaves) are face cards. So, there are 12 face cards in the deck of 52 playing cards. Worked-out problems on Playing cards probability:
What is the number of favourable outcomes in a deck of cards?
Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards. Number of favourable outcomes i.e. ‘a king of red colour’ is 2 out of 52 cards. Number of favourable outcomes i.e. ‘a card of diamond’ is 13 out of 52 cards. Total number of king is 4 out of 52 cards.
What is the probability of getting a card of diamond?
(iv) a card of diamond. Number of favourable outcomes i.e. ‘a card of diamond’ is 13 out of 52 cards. Therefore, probability of getting ‘a card of diamond’ Number of favorable outcomes P(D) = Total number of possible outcome = 13/52 = 1/4 (v) a king or a queen. Total number of king is 4 out of 52 cards.
What is the probability of getting ‘2’ of Spades?
Number of favourable outcomes i.e. ‘2’ of spades is 1 out of 52 cards. Therefore, probability of getting ‘2’ of spade Number of favorable outcomes P(A) = Total number of possible outcome = 1/52 (ii) a jack. Number of favourable outcomes i.e. ‘a jack’ is 4 out of 52 cards. Therefore, probability of getting ‘a jack’
What is the probability of getting ‘neither a heart nor a red king?
Cards of hearts and diamonds are red cards. Number of red kings in red cards = 2 . Therefore, neither a heart nor a red king = 39 – 1 = 38 [Since, 1 red king is already included in the 13 hearts so, here we will take number of red kings is 1] Therefore, probability of getting ‘neither a heart nor a red king’ Number of favorable outcomes
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What is the probability of choosing two letters from four letters?
Hence the required probability is 2/12 = 1/6. Two letters from four letters of the word LIME can be chosen without replacement in 4C2 = 6 ways. Note that this sample is unordered. The letters L and M can therefore be chosen in 1 way. Hence the required probability is 1/6.
What is the probability that the letters L and M are ordered?
If the letters are chosen one by one at random without replacement, the the two letters can be chosen in 4*3 = 12 ways. This sample is an ordered sample. Hence the letters L and M can be chosen in 2 ways ( L followed by M or M followed by L). Hence the required probability is 2/12 = 1/6.