What is the probability of having two boys and one girl?

What is the probability of having two boys and one girl?

Out of those, the permutations with two boys and one girl are BBG, BGB, and GBB. The answer is the ratio of how many choices fit your conditions to the total number of possibilities, 3 8. So the answer is 3 8. Another way to think about it. After a first boy we need one of each (50\%). After a first girl we must have only boys (25\%).

How many permutations are there for 2 boys and 1 girl?

P ( 2 boys, 1 girl) = P ( B B G) + P ( B G B) + P ( G B B) = 1 2 1 2 1 2 + 1 2 1 2 1 2 + 1 2 1 2 1 2 = 3 8. Em. Em. Since there are two genders and three children, that’s 2 3 = 8 permutations. You had three permutations. They would be BBB, BBG, BGB, BGG, GBB, GBG, GGB, and GGG.

What are the chances of having a second child with recessive disorder?

For example, if a couple has a child with an autosomal recessive disorder, the chance of having another child with the disorder is still 25 percent (or 1 in 4). Having one child with a disorder does not “protect” future children from inheriting the condition.

What is the ratio of the average family with one boy?

That is, the average family has 1 boy. We already know that all families have 1 girl, so the ratio will over time even out to be 1 / 1 = 1. The random variable X is known as a geometric random variable.

What is the probability of having at least one child?

To have at least one child of each sex, we need to subtract out from the 8 ways the genders can be the 2 that are single sex (i.e. all boys and all girls). So we get: Roy Ø. It is customary to say that the probability of getting a boy is 1 2.

What is the probability of having 3 boys in 5C3?

Now, 3 boys can be chosen from 5 boys in 5C3 = 5!/ (3!×2!) = 10 ways, and the remaining 2 children will be girls in each case. Hence, the probability=10/32=5/18 Answer.

What are the odds of having a baby in each generation?

You can see that the chance of having at least one boy is 1 / 2 in the first generation, 3 / 4 in the second, and 7 / 8 in the third. This generalizes to ( 2 n − 1) / 2 n in the nth generation.