Table of Contents

## How do you find the area of a shaded area?

Find the area of the shaded region by subtracting the area of the small shape from the area of the larger shape. The result is the area of only the shaded region, instead of the entire large shape. In this example, the area of the circle is subtracted from the area of the larger rectangle.

### How do you find the area of the shaded surface in square?

The area of the shaded region is the difference between the areas of the rectangle and the square. The dimensions of the rectangle are 6 by 8 and so the area is 6 times 8 , that is 48 square units. Each side of the square measures 2 units and so the area is 2 times 2 , that is 4 square units.

#### How do you write an equation for a shaded graph?

There are three steps:

- Rearrange the equation so “y” is on the left and everything else on the right.
- Plot the “y=” line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
- Shade above the line for a “greater than” (y> or y≥) or below the line for a “less than” (y< or y≤).

**What is the area of the shaded region using the formula?**

Well, the formula for area of a circle is pi r squared, or r squared pi. So the radius is 3. So it’s going to be 3 times 3, which is 9, times pi– 9 pi. So we have 100 minus 9 pi is the area of the shaded region. And we got it right.

**How do you find the area of a region with two lines?**

Instead we rely on two vertical lines to bound the left and right sides of the region as we noted above Here is the integral that will give the area. Example 3 Determine the area of the region bounded by y = 2×2+10 y = 2 x 2 + 10 and y =4x+16 y = 4 x + 16 .

## What is the vertical line dividing the black shaded region?

The vertical line dividing the black shaded region from the white un-shaded region is z = 1.53. Using the z-table, we will find the area to the left of z = 1.53.

### How do you find the area to the right of Z?

To find the area to the right, we first find the area to the left of the z-score, then we subtract that area from 1. By simple subtraction from 1, or 100\%, we have 1 –.9370 =.0630 Therefore, the area to the right of z = 1.53 is.0630.