How many numbers between 1 and 1000 are divisible by 7 A 777 C 143 B 142 D none of these?

How many numbers between 1 and 1000 are divisible by 7 A 777 C 143 B 142 D none of these?

Because to get numbers between 1 to 1000 which are divisible by 7 can be calculated very easily just only by dividing 1000 by 7, 1000/7=142.8571, so 142 numbers are there between 1 to 1000 are divisible by 7, thus option (b) is the right answer.

How many numbers are divisible by 7?

128 three digit
Hence, 128 three digit numbers are divisible by 7.

How many numbers from 0 to 999 are divisible by either 5 or 7?

So there are 142 + 199 – 28 = 313 numbers divisible by 5 or 7 in the given set of numbers from 0 to 999. The other numbers are not divisible by either 5 or 7. There are 1000 – 313 = 687 such numbers. The required number of numbers not divisible by 5 or 7 in the set of numbers from 0 to 999 is 687.

How many natural numbers are there between 3 and 200 which are divisible by 7?

There are 28 natural numbers divisible by 7 between 3 and 200.

How many natural numbers are between 1 and 1000 are divisible by 5?

Therefore there are 200 numbers from 1 to 1000 that are divisible by 5.

How many numbers between 300 and 1000 are divisible by 7 and 8 both?

Answer: Hence, there are 12 numbers in between 300 and 1000 which are divisible by 7 and 8.

How many three digit numbers are there which are divisible by 9?

100 three-digit numbers
Hence, there are 100 three-digit numbers divisible by 9.

How many 4 digits numbers are there divisible by 9?

Examples. 829. 8+2+9=19. 27–19=8, 8298 is divisible by 9.

How many whole numbers between 0 and 999 contain the digit 5?

From the range of numbers 0 to 99, the digit 5 appears 20 times.

How many numbers are there between 1 and 800 that are divisible by 5 or 7 but not by 35?

How many numbers are there which are divisible by neither 5 nor 7, in the set {200, 201, 202, ….., 798, 799, 800}? Because total numbers in the given set are : (800 – 200) + 1 = 601. Since we have calculated number of numbers which are divisible by either 5 or 7 or both in just earlier question : (121 + 86) – 17 = 190.

How many natural numbers are there between 3 and 7?

Answer: 4 , 5 , 6 are the natural numbers between 3 and seven…

How many natural numbers are there between 1 and 200 are exactly divisible by 3 9 and 27?

171, 180 and 198. There are 15 such numbers.

How many natural numbers between 101 and 999 are divisible by 2-5?

Hence there are 89 natural numbers between 101 and 999 which are divisible by both 2 and 5. Is there an error in this question or solution?

How many integers between 110 and 999 are divisible by 10?

The numbers between 101 and 999 which are divisible by 10 are those in the Arithmetic Progression sequence: Therefore n = 88 + 1 = 89. And therefore, there are 89 integers between 110 and 999 which are divisible by 10. 110 120 130 140 150 160 170 180 190 200 210 220 230 240 250 260 270 280 290 300 310 320 330 340 350 360 370 380 390 40

How to find a number divisible by 35 between 1 and 999?

You have to find out a number which is divisible by 35 in the numbers between 1 and 999. The above sequences are in AP with common difference (d) =35, 1st term (a) =35 and last term (Tn)=980. Since, Tn=a+ (n-1)*d where n=no.

Which three-digit number is divisible by both 2 and 5?

For a natural number to be divisible by 5. its ending digit must be either 0 or 5. Therefore, a natural number, which is divisible by both 2 and 5, must have its ending digit equals to 0. Now, back to your question, a natural three-digit number between 101 and 999, which is divisible by both 2 and 5, must have its ending digit equals to 0.