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What is the radius of the circumcircle of the triangle with sides 6cm 8cm and 10cm?

Posted on July 16, 2021 by Author

Table of Contents

  • 1 What is the radius of the circumcircle of the triangle with sides 6cm 8cm and 10cm?
  • 2 What is the radius of a circle inscribed in a triangle with side of length 12cm 35cm and 37cm?
  • 3 How do you find the circumradius of a right angled triangle?
  • 4 What is the radius of a circle inscribed in a triangle with?
  • 5 How do you find the radius of an inscribed circle in a triangle?
  • 6 What is circumcircle formula?
  • 7 What is the circumradius of an equilateral triangle of sides 8 cm?
  • 8 What is the radius of the triangle 18/24/30?

What is the radius of the circumcircle of the triangle with sides 6cm 8cm and 10cm?

Explanation – Hence, circumradius is 5 cm.

What is the radius of a circle inscribed in a triangle with side of length 12cm 35cm and 37cm?

We have to find the radius of inscribed circle in a triangle with sides of length 12cm , 35 cm and 37 cm. solution : see diagram, let O is the centre of inscribed circle in a triangle ∆ABC. Therefore the radius of circle is 5cm.

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How do you find the circumradius of a right angled triangle?

The circumradius of a right angled triangle is half the hypotenuse and the centre is the midpoint of the hypotenuse. Circum radius of a right angled ∆ is the half of its hypotenuse.

How do you find the radius of an incircle of a right angled triangle?

To find the area of a circle inside a right angled triangle, we have the formula to find the radius of the right angled triangle, r = ( P + B – H ) / 2. Given the P, B and H are the perpendicular, base and hypotenuse respectively of a right angled triangle. where π = 22 / 7 or 3.14 and r is the radius of the circle.

What is the radius of Incircle of a triangle with sides 18 24 30?

Let ABC be a triangle with AB=18cm, BC=24cm and AC=30cm and a circle is inserted in triangle with radius ‘r’. Let O be the centre of the circle. So, the answer is C. Note: There is a shortcut to solve this problem using the formula, radius = (a+b−c2) if a, b are the sides and c is the hypotenuse of the triangle.

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What is the radius of a circle inscribed in a triangle with?

WE can see from the figure that the radius of the inscribed circle is perpendicular to the corresponding sides, so OD, OF, OE are perpendicular to AB, BC and AC respectively. Hence the radius of the inscribed circle is 3.

How do you find the radius of an inscribed circle in a triangle?

For any triangle △ABC, let s = 12 (a+b+c). Then the radius r of its inscribed circle is r=(s−a)tan12A=(s−b)tan12B=(s−c)tan12C. We also see from Figure 12 that the area of the triangle △AOB is Area(△AOB)=12base×height=12cr.

What is circumcircle formula?

Properties and Formulas The area and perimeter of a circumcircle are the same as they would be for any other circle. If a circle has radius r, then the formulas for the area and perimeter of that circle, are as follows: Area of a circle = πr2. Perimeter of a circle = 2πr.

What is the radius of inscribed circle with 12 sides?

Radius found to be => 6 units. Sum of all sides, of this series of Triangles, /12 = Radius of inscribed circle. Radius = 72/12 = 6. Hope that helps. Re; formulae in other answers, thank you each.

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What is the radius of the incircle of the triangle?

radius of the incircle of triangle= area/semi perimeter. p is half the perimeter, or. P=(18+24+30)/2 = 36. A=square root of (36(36-18)(36-24)(36-30)) =square root of (36*18*12*6) =216 s.cm. radius of the incircle of triangle= 216/36=6cm.

What is the circumradius of an equilateral triangle of sides 8 cm?

Maths keeps one mentally active. The circumradius of an equilateral triangle of sides of 8 cm = 8/√3 = 4.618802154 or 4.62 cm. With TrianCal, circumradius ≈ 4.62 cm. Since it is a equilateral triangle, we can easily find its circumstances radius.

What is the radius of the triangle 18/24/30?

This is a right angled triangle. Essentially, this is the basic 3–4–5 right angled triangle with each side 6 times the original. The in-radius of the basic triangle is (3+4 – 5) /2 [Sum of the legs – Hypotenuse]/2 or 1 unit and hence that of the required triangle will be 6*1=6 units. 18,24,30 is a right triangle.

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